1.

Which of the following is paramagentic?A. `O_(2)^(-)`B. `CN`C. `CO`D. `NO^(+)`

Answer» Correct Answer - a
`CN^(-), CO and NO^(+)` are isolectronic with `14` electron each and there is no unpaired electrons in the `MO` configuration of these species. So these are diamagnetic , `O_(2)^(+)` is paramagnetic due to the presence of one unpaired electron.
`(CN^(-), CO, CO^(+))14 = sigma 1s^(2), sigma ** 1s^(2), sigma 2s^(2), sigma** 2s^(2), sigma 2p_(x)^(2)`
`pi 2p_(z)^(2) = pi 2p_(z)^(2)` (No unpaired electron diamagnetic)
`O_(2^(+)) = sigma 1s^(2), sigma ** 1s^(2), sigma 2s^(2), sigma** 2s^(2), sigma 2p_(x)^(2)`
` pi 2p_(x)^(2) = pi 2p_(z)^(2), pi ** 2p_(y)^(2) = pi ** 2p_(z)^(1)`
(One unpaired electron , paramagnetic)


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