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Which of the following is paramagentic?A. `O_(2)^(-)`B. `CN`C. `CO`D. `NO^(+)` |
Answer» Correct Answer - a `CN^(-), CO and NO^(+)` are isolectronic with `14` electron each and there is no unpaired electrons in the `MO` configuration of these species. So these are diamagnetic , `O_(2)^(+)` is paramagnetic due to the presence of one unpaired electron. `(CN^(-), CO, CO^(+))14 = sigma 1s^(2), sigma ** 1s^(2), sigma 2s^(2), sigma** 2s^(2), sigma 2p_(x)^(2)` `pi 2p_(z)^(2) = pi 2p_(z)^(2)` (No unpaired electron diamagnetic) `O_(2^(+)) = sigma 1s^(2), sigma ** 1s^(2), sigma 2s^(2), sigma** 2s^(2), sigma 2p_(x)^(2)` ` pi 2p_(x)^(2) = pi 2p_(z)^(2), pi ** 2p_(y)^(2) = pi ** 2p_(z)^(1)` (One unpaired electron , paramagnetic) |
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