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Which of the following is the right electronic confiuration of the element palladium `(Z = 46)`?A. `[Kr] 4d^(10)`B. `[Kr] 4d^(9)5s^(1)`C. `[kr] 4d^(8)5s^(2)`D. `[Kr]4d^(7)5s^(3)` |
Answer» Correct Answer - A Palladium has `46` electrons. We need `36` electrons `(2+8 +8 +18)` to complete the fourth period, leaving us with `10` more electrons to distribute among the `5s` (maximum `2e^(-)` and `4d` (maximum `10e^(-)s`) subshell. The three choice are `(1),(2)` and `(3)`. Since atomic palladium is diamagnetic, its electron configuration must be `1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)4s^(2)4p^(6)4d^(10)` or simply `[Kr] 4d^(10)` Note that a diamagnetic substance is a substance that is not attracted by a magnetic field or is very slightly repelled by such a fiels. This property generally means that the sunstance has only paired electrons. |
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