InterviewSolution
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InterviewSolution
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which of the following reactions will get affected by increase in pressure ? Also mention whether the change will cause the reaction to go the right or left direction. (i) `CH_(4)(g)+2S)_(2) (g) hArr CS_(2) (g) + 2H_(2)S(g)` (ii) `CO_(2) (g) +C(s) hArr 2CO (g)` (iii) `4NH_(3)(g) +5O_(2)(g) hArr 4NO (g) + 6H_(2)O(g)` (iv) `C_(2)H_(4)(g) +H_(2)(g) hArr C_(2)H_(6) (g)` (v) `COCI_(2)(g) hArr CO(g) +CI_(2)(g)` (vi) `CaCO_(3)(g) hArr CaO(s)+CO_(2)(g)` |
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Answer» Only those reactions will be affected by increasing the pressure in which the number of moles of the gaseous reactants and products are different `(n_(p) ne n_(r))` (gaseous). With the exception of the reaction (1),all the remaining five reactions will get affected by increasing the pressure . In general. the reaction will go to the left if `n_(p) gt n_(r)` The reaction will go to the right if `n_(p) lt n_(r)` Keeping this in mind. (i) Increases in pressure will not affect equilibrium because `n_(p) =n_(r) =3.` (ii) Increase in pressure will favour backward reaction because `n_(p)(2) gt n_(r) (1)` (iii) Increase in pressure will favour backward reaction because `n_(p) (10) gt n_(r) (9)` (iv) Increase in pressure will favour forward reaction because`n_(p)(1) lt n_(r) (2)` (v) Increase in pressure will favour backward reaction because `n_(p) (2) gt n_(r)(1)` (vi) Increase in pressure will favour backward reaction because `n_(p) (1) gt n_(r) (0)` |
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