A. 0.2 mole of sucrose (C₁₂H₂₂O₁₁):

Given: Number of moles = 0.2

Molar mass of C₁₂H₂₂O₁₁ = 342 g/mol

To find out the mass of sucrose, apply the formula given:

Number of moles = \(\frac{Mass}{Molar\,mass}\)

⇒ 0.2 = \(\frac{mass}{342\,g/mol}\)

⇒ Mass = 0.2 mol × 342g/mol

⇒ Mass = 68.4g

Thus, the mass of sucrose is 68.4 g.

B. 2 moles of CO₂:

Given: Number of moles = 2

Molar mass of CO₂ = 44 g/mol

To find out the mass of sucrose, apply the formula given:

⇒ Mass = 2 mol × 44g/mol

⇒ Mass = 88g

Thus, the mass of CO₂ is 88 g.

C. 2 moles of CaCO₃:

Given: Number of moles = 2

Molar mass of CaCO₃ = 40 + 12 + 3× 16 = 100 g/mol

To find out the mass of sucrose, apply the formula given:

Number of moles = \(\frac{Mass}{Molar\,mass}\)

⇒ 2 = \(\frac{mass}{100\,g/mol}\)

⇒ Mass = 2 mol × 100g/mol

⇒ Mass = 200g

Thus, the mass of CaCO₃ is 200 g.

D. 10 moles of H₂O:

Given: Number of moles = 10

Molar mass of H₂O = 18 g/mol

To find out the mass of sucrose, apply the formula given:

Number of moles = \(\frac{Mass}{Molar\,mass}\)

⇒ 10 = \(\frac{mass}{18\,g/mol}\)

⇒ Mass = 10 mol × 18g/mol

⇒ Mass = 180g

Thus, the mass of H₂O is 180 g.

Hence, the option C is correct which has higher mass.