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Why is the work done on an object moving with uniform circular motion zero? ​

Answer» <html><body><p>Work done is equal to Force (acting in the direction of displacement) times the displacement i.e. W=F.S where (.) is dot product. For the work done we need component of force along the direction of displacement but displacement and force are 90°, at each and <a href="https://interviewquestions.tuteehub.com/tag/every-976721" style="font-weight:bold;" target="_blank" title="Click to know more about EVERY">EVERY</a> point on the <a href="https://interviewquestions.tuteehub.com/tag/circular-916697" style="font-weight:bold;" target="_blank" title="Click to know more about CIRCULAR">CIRCULAR</a> track and <a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> the component of force along the direction of displacement will always be zero in case of a body moving in a circular track or a body performing circular motion. We know W=F.S or F.Scos(θ), since body is moving in circular track <a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a>(θ)=0 , and hence whole <a href="https://interviewquestions.tuteehub.com/tag/term-1241851" style="font-weight:bold;" target="_blank" title="Click to know more about TERM">TERM</a> will be 0 i.e. Work done will be 0.</p></body></html>


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