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Write the cell reaction for which `E_(cell) =E_(cell)^(0) -(RT)/(2F)ln ""([Mg^(2+)])/([Ag^(+)]^(2))` |
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Answer» Given `E_(cell) =E_(cell)^(0) -(RT)/(2F) ln ""([Mg ^(2+)])/([Ag^(+)]^(2))` The cell reaction is `Mg_((s))//Mg _((aq))^(2+)||Ag_((aq))^(+)|Ag_((s))` `Mg yo Mg^(2+)+2e^(-)` (Oxidation) `2 Ag^(+) +2e^(-) to Ag` (Reduction) `overline underline(Mg+ 2 Ag^(+)to Mg^(+2)+Ag)` |
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