Write the hydrolysis products of XeF2 XeF4, XeF6. – InterviewSolution

InterviewSolution

1.

Write the hydrolysis products of XeF2 XeF4, XeF6.

Answer»

(i) 2XeF₂ (s) + 2H₂O(l) → 2Xe (g) + 4 HF(aq) + O₂(g

(ii) 6XeF₄ + 12 H₂O → 4Xe + 2XeO₃ + 24 HF + 3O₂

(iii) XeF₆ + 3 H₂O → XeO₃ + 6 HF

Partial hydrolysis of XeF₆ gives oxyfluorides,

XeF₆ + H₂O → XeOF₄ + 2HF

XeF₆ + 2 H₂O → XeO₂F₂ + 4HF

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