InterviewSolution
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InterviewSolution
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Write the strucrtures of the products. `(CH_(3))_(2)CH-OCH_(3)underset("heat")overset("HI(excess)")rarr` |
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Answer» In this case, the ethereal oxygen will b initially protonated by the `H^(+)`. This is followed by the attack of `I^(-)` on the protonated ether and this prefers ot combine with `CH_(3)` group rather than isopropyl group. The reaction proceeds as follows : `underset("Methyl isopropyl ether")((CH_(3))_(2)CH-OCH_(3))overset(H^(+))rarr(CH_(3))_(2)CH-underset("Protonated ether")underset(H)underset(|)overset(o+)O-CH_(3)overset(I^(-))rarr(CH_(3))_(2)underset("alcohol")underset("Isopropyl")(CHOH)+underset("iodide")underset("Methyl")(CH_(3)I)overset(HI)rarrunderset("Isopropyl iodide")((CH_(3))_(2)CHI)+H_(2)O` Thus, `CH_(3)I and (CH_(3))_(2)CHI` are formed as the products. |
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