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You are given the electronic configuration of five neutral atoms - AB, B, C, D and E ` A - 1s^(2) 2s^(2) 2p^(6) 3s^(2), B - 1s^(2), 2s^(2) 2p^(6) 3s^(1), C - 1s^(2) 2s^(2) 2p^(1) , D- 1s^(2) 2s^(2) 2p^(5), E - 1s^(2) 2s^(2) 2p^(6)` Write the empirical formula for the substance containing (i) A and D (ii) B and D (iii) only D (iv) only E ? |
Answer» (i) Empirical formula of the compound formed by A and D `AD_(2)` as A has two valence electrons and D has seven. Atom A transfers its two electrons to two D atoms to complete their octets . (ii) Empirical formula of the compound formed by B and D is BD as B transfers its one electron to D. (iii) `D_(2)` as both the atoms of D share one electron each to form a covelent bond (iv) Since it is noble gas , no compound is formed . |
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