InterviewSolution
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InterviewSolution
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You are given the following species `C_(2)^(+), O_(2)^(2+), Be_(2), C_(2), O_(2)^(2-), C_(2)^(-) ` Arrange them in order of increasing bond strength giving reason. |
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Answer» `C_(2)^(+)(11)= sigma_(1s)^(2)sigma_(1s)^(**2)sigma_(2s)^(2)sigma_(2s)^(**2) (pi_(2P_(x))^(2)= pi_(2p_(y))^(1))` Bond order = ` (1)/(2) (N_(b)- N_(a)) = (1)/(2) (7-4) = 1.5` `C_(2)^(2+)(14)= sigma_(1s)^(2)sigma_(1s)^(**2)sigma_(2s)^(2)sigma_(2s)^(**2)sigma_(2p_(z))^(2) (pi_(2P_(x))^(2)= pi_(2p_(y))^(1))` Bond orger ` = (1)/(2) (10 - 4) = 3 ` `Be_(2) (8) = sigma_(1s)^(2)sigma_(1s)^(**2)sigma_(2s)^(2)sigma_(2s)^(**2)` Bond order `= (1)/(2) (4-4) = 0 ` `C_(2)(12)= sigma_(1s)^(2)sigma_(1s)^(**2)sigma_(2s)^(2)sigma_(2s)^(**2)sigma_(2p_(z))^(2) (pi_(2P_(x))^(2)= pi_(2p_(y))^(2))` Bond order ` = (1)/(2) (8-4) = 2 ` `O_(2)^(2-) (18) = sigma_(1s)^(2)sigma_(1s)^(**2)sigma_(2s)^(2)sigma_(2s)^(**2)sigma_(2p_(z))^(**2) (pi_(2P_(x))^(2)= pi_(2p_(y))^(2)) (pi_(2P_(x))^(**2)= pi_(2p_(y))^(**2))` Bond order ` (1)/(2) (10 - 8 ) = 1 ` `C_(2)^(-)(13)= sigma_(1s)^(2)sigma_(1s)^(**2)sigma_(2s)^(2)sigma_(2s)^(**2) (pi_(2P_(x))^(2)= pi_(2p_(y))^(2))sigma_(2p_(z))^(1)` Bond order ` = (1)/(2) (9 - 4) = 2.5 ` Greater the bond order, greater is the bond strength . Hence, increasing order of bond strength will be `Be_(2) lt O_(2)^(2-) lt C_(2)^(+) lt C_(2) lt C_(2)^(-) lt O_(2)^(2+)` . |
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