Explore topic-wise InterviewSolutions in Physics.

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Physics knowledge and support exam preparation. Choose a topic below to get started.

501.

The focal length ſ =(10cm). At what distance object should be placed to get an image twice size of object​

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><p>Answer is <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> in the <a href="https://interviewquestions.tuteehub.com/tag/pic-591410" style="font-weight:bold;" target="_blank" title="Click to know more about PIC">PIC</a>. </p><p><strong><a href="https://interviewquestions.tuteehub.com/tag/hope-25911" style="font-weight:bold;" target="_blank" title="Click to know more about HOPE">HOPE</a></strong><strong> </strong><strong>this</strong><strong> </strong><strong><a href="https://interviewquestions.tuteehub.com/tag/helps-1018140" style="font-weight:bold;" target="_blank" title="Click to know more about HELPS">HELPS</a></strong><strong> </strong><strong>you</strong><strong> </strong></p></body></html>
502.

Igskhsyelhdgkdisyjgsgskgsigkskgskgs

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><p>nnbbwnan ananananannanansnnwnw</p></body></html>
503.

HEYLO!up for c..h.a.t ?wzymrrvxpp​

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><p>he he he he he he he he he he he he </p></body></html>
504.

Find the electric field intensity due to cylindrical wire.​

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><p>Electric Field:<a href="https://interviewquestions.tuteehub.com/tag/cylinder-942617" style="font-weight:bold;" target="_blank" title="Click to know more about CYLINDER">CYLINDER</a> of Charge</p><p></p><p>Considering a Gaussian surface in the form of a cylinder at radius r &gt; R, the electric field has the same <a href="https://interviewquestions.tuteehub.com/tag/magnitude-1083080" style="font-weight:bold;" target="_blank" title="Click to know more about MAGNITUDE">MAGNITUDE</a> at every <a href="https://interviewquestions.tuteehub.com/tag/point-1157106" style="font-weight:bold;" target="_blank" title="Click to know more about POINT">POINT</a> of the cylinder and is directed <a href="https://interviewquestions.tuteehub.com/tag/outward-1143291" style="font-weight:bold;" target="_blank" title="Click to know more about OUTWARD">OUTWARD</a>. The electric flux is then just the electric field times the area of the cylinder</p><p><strong></strong></p><p></p></body></html>
505.

At given t taken a body at rest which then moves with an acceleration, after 3 sec its momentum​

Answer» <html><body><p><strong>Answer:</strong></p><p>We know force F=mass×acceleration-------(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)</p><p>Given time = <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> seconds</p><p>We can rewrite the <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a> (1) as </p><p></p><p>Force=mass× </p><p>Time(t)</p><p>Final(v)-Initial <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a>(u)</p><p></p><p> --------(2)</p><p></p><p>Also change in momentum dp=p </p><p>final</p><p></p><p> −p </p><p>initial</p><p></p><p> = mass×change in velocity</p><p></p><p>Equation (2) becomes F= </p><p>dt</p><p>dp</p><p></p><p> </p><p>Fdt=dp</p><p>Integrating the above equation we get:</p><p></p><p>F∫ </p><p>0</p><p>2</p><p></p><p> dt=∫ </p><p>p </p><p>i</p><p></p><p> </p><p>p </p><p>f</p><p></p><p> </p><p></p><p> dp</p><p></p><p>30×2 = P </p><p>f</p><p></p><p> −P </p><p>i</p><p></p><p> </p><p>Therefore change in momentum = 60 kg m/s </p></body></html>
506.

Replace the "C" in Covid-19 by the first letter of your name.Mine will be Rovid-19.​

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><p><a href="https://interviewquestions.tuteehub.com/tag/ohh-583380" style="font-weight:bold;" target="_blank" title="Click to know more about OHH">OHH</a> haaa</p><p><strong>Explanation:</strong></p><p>very nice</p><p>please <a href="https://interviewquestions.tuteehub.com/tag/mark-555248" style="font-weight:bold;" target="_blank" title="Click to know more about MARK">MARK</a> me as <a href="https://interviewquestions.tuteehub.com/tag/brainlist-2485655" style="font-weight:bold;" target="_blank" title="Click to know more about BRAINLIST">BRAINLIST</a></p></body></html>
507.

Can there be an electric circuit be complete without a key or switch?

Answer» <html><body><p>If a switch is absent because it has been physically removed, leaving dangling <a href="https://interviewquestions.tuteehub.com/tag/wires-1457870" style="font-weight:bold;" target="_blank" title="Click to know more about WIRES">WIRES</a> (power wiring) or <a href="https://interviewquestions.tuteehub.com/tag/empty-2611346" style="font-weight:bold;" target="_blank" title="Click to know more about EMPTY">EMPTY</a> solder pads (electronics) , then current will not <a href="https://interviewquestions.tuteehub.com/tag/flow-993213" style="font-weight:bold;" target="_blank" title="Click to know more about FLOW">FLOW</a>- it's functionally equivalent to a switch always in its "off" state. Wires are cheaper than switches.</p></body></html>
508.

Answer the below question

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a>:</strong></p><p>xkgpxoydHIDIEZIFYZUSGDLHXDICHCOGCLGXOSGZFOFOFGFFFOOOFTPTTTzpgzOGXOFZ</p></body></html>
509.

Answer the below given question

Answer» <html><body><p> </p><p></p><p> <a href="https://interviewquestions.tuteehub.com/tag/open-586655" style="font-weight:bold;" target="_blank" title="Click to know more about OPEN">OPEN</a> the <a href="https://interviewquestions.tuteehub.com/tag/attachment-385146" style="font-weight:bold;" target="_blank" title="Click to know more about ATTACHMENT">ATTACHMENT</a> </p><p><a href="https://interviewquestions.tuteehub.com/tag/please-601513" style="font-weight:bold;" target="_blank" title="Click to know more about PLEASE">PLEASE</a> <a href="https://interviewquestions.tuteehub.com/tag/mark-555248" style="font-weight:bold;" target="_blank" title="Click to know more about MARK">MARK</a> <a href="https://interviewquestions.tuteehub.com/tag/brainliest-1995348" style="font-weight:bold;" target="_blank" title="Click to know more about BRAINLIEST">BRAINLIEST</a></p><p></p></body></html>
510.

Explain angle of friction and it's relation with co-efficient of friction​

Answer» <html><body><p>okkkkkkkk I'll okkkkkkkkkkkk okkkkkkkkkkkk</p></body></html>
511.

Define conduction ? give one example where heat is transferred by the process of conduction .​

Answer» <html><body><p><em><a href="https://interviewquestions.tuteehub.com/tag/conduction-928825" style="font-weight:bold;" target="_blank" title="Click to know more about CONDUCTION">CONDUCTION</a> is the transfer of energy in the form of heat or electricity from one <a href="https://interviewquestions.tuteehub.com/tag/atom-887280" style="font-weight:bold;" target="_blank" title="Click to know more about ATOM">ATOM</a> to another within an <a href="https://interviewquestions.tuteehub.com/tag/object-11416" style="font-weight:bold;" target="_blank" title="Click to know more about OBJECT">OBJECT</a> by direct contact. ... Some examples of conduction of heat are accidentally touching a hot pot, or when a heating <a href="https://interviewquestions.tuteehub.com/tag/pad-590012" style="font-weight:bold;" target="_blank" title="Click to know more about PAD">PAD</a> is applied to you <a href="https://interviewquestions.tuteehub.com/tag/directly-955045" style="font-weight:bold;" target="_blank" title="Click to know more about DIRECTLY">DIRECTLY</a> and warms your muscles</em></p></body></html>
512.

एक अच्छा खिलाड़ी सफलता पाने के लिए क्या करता है ? *(a) ਸਖ਼ਤ ਮਿਹਨਤ ਕਰਦਾ ਹੈ/ कठिन परिश्रम करता है(b) ਨਵੀਂ ਤਕਨੀਕ ਸਿੱਖਣ ਦੀ ਕੋਸ਼ਿਸ਼ ਕਰਦਾ ਹੈ / वह नई तकनीक सीखने की केशिश करता है ।He tries to learn new techniques.(c)ਆਪਣੀ ਖੇਡ ਦਾ ਚੰਗਾ ਪ੍ਰਦਰਸ਼ਨ ਅਤੇ ਜਿੱਤਣ ਲਈ ਪੂਰਾ ਜ਼ੋਰ ਲਗਾਉਂਦਾ ਹੈ/वह खेल का बढ़िया प्रदर्शन करता है और जीतने की पूरी कोशिश करता है /He does his best to win the game.(d)ਉਪਰੋਕਤ ਸਾਰੇ/ ऊपर के सभी/ All of the above

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><p><a href="https://interviewquestions.tuteehub.com/tag/option-25810" style="font-weight:bold;" target="_blank" title="Click to know more about OPTION">OPTION</a> (D) is <a href="https://interviewquestions.tuteehub.com/tag/right-1188951" style="font-weight:bold;" target="_blank" title="Click to know more about RIGHT">RIGHT</a> All of the above</p></body></html>
513.

Find total resistance for parallel combination

Answer» <html><body><p><strong>Answer:</strong></p><p>The sum of the currents through each path is <a href="https://interviewquestions.tuteehub.com/tag/equal-446400" style="font-weight:bold;" target="_blank" title="Click to know more about EQUAL">EQUAL</a> to the total current that <a href="https://interviewquestions.tuteehub.com/tag/flows-993448" style="font-weight:bold;" target="_blank" title="Click to know more about FLOWS">FLOWS</a> from the source. You can <a href="https://interviewquestions.tuteehub.com/tag/find-11616" style="font-weight:bold;" target="_blank" title="Click to know more about FIND">FIND</a> total <a href="https://interviewquestions.tuteehub.com/tag/resistance-1186351" style="font-weight:bold;" target="_blank" title="Click to know more about RESISTANCE">RESISTANCE</a> in a Parallel circuit with the following formula: 1/Rt = 1/R1 + 1/R2 + 1/R3 +... If one of the parallel <a href="https://interviewquestions.tuteehub.com/tag/paths-1148968" style="font-weight:bold;" target="_blank" title="Click to know more about PATHS">PATHS</a> is broken, current will continue to flow in all the other paths.</p></body></html>
514.

Redraw the circuit of Questions 1, putting in an ammeter to measure the current through the resistors and a voltmeter to measure the potential difference across the 12 Ω resistor. What would be the readings in the ammeter and the voltmeter ?​

Answer» <html><body><p><strong>Answer:</strong></p><p>An ammeter should be connected in the circuit in series with the resistors. To measure the potential difference across the resistor it should be connected in parallel, </p><p>Ohm’s <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a> can be used to obtain the readings of ammeter and voltmeter. <a href="https://interviewquestions.tuteehub.com/tag/according-366619" style="font-weight:bold;" target="_blank" title="Click to know more about ACCORDING">ACCORDING</a> to Ohm’s law,</p><p>V = <a href="https://interviewquestions.tuteehub.com/tag/ir-500478" style="font-weight:bold;" target="_blank" title="Click to know more about IR">IR</a>,</p><p>Where,</p><p>Potential difference, V = 6 V</p><p>Current flowing through the circuit/resistors = I</p><p>Resistance of the circuit, R = 5 + <a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a> + 12 = 25ohm</p><p>I = V/R = 6/25 = 0.24 A</p><p>Potential difference across 12ohm resistor = V1</p><p>Current flowing through the 12ohm resistor, I = 0.24 A</p><p>Therefore, using Ohm’s law, we obtain</p><p>V1 = IR = 0.24 x 12 = 2.88 V</p><p><strong>Therefore, the reading of the ammeter will be 0.24 A.</strong></p><p><strong>The reading of the voltmeter will be </strong><strong> 2.88 V</strong></p></body></html>
515.

Find the angles respectively of a ∆PQR. For each of the following cases, state whether EF || QR: (i) PE = 3.9 cm, EQ = 3 cm, PF = 3.6 cm and FR = 2.4 cm (ii) PE = 4 cm, QE = 4.5 cm, PF = 8 cm and RF = 9 cm (iii) PQ = 1.28 cm, PR = 2.56 cm, PE = 0.18 cm and PF = 0.36 cmKoi mujhse friendship karega :)​

Answer» <html><body><p><strong>Explanation:</strong></p><p>E and F are two points on side PQ and PR in △PQR. </p><p>(i) PE=3.9 cm, EQ=3 cm and PF=3.6 cm, FR=2.4 cm</p><p>Using <a href="https://interviewquestions.tuteehub.com/tag/basic-15343" style="font-weight:bold;" target="_blank" title="Click to know more about BASIC">BASIC</a> proportionality theorem,</p><p>∴ </p><p>EQ</p><p>PE</p><p> </p><p> = </p><p>3</p><p>3.9</p><p> </p><p> = </p><p>30</p><p>39</p><p> </p><p> = </p><p>10</p><p>13</p><p> </p><p> =1.3 </p><p></p><p>FR</p><p>PF</p><p> </p><p> = </p><p>2.4</p><p>3.6</p><p> </p><p> = </p><p>24</p><p>36</p><p> </p><p> = </p><p>2</p><p>3</p><p> </p><p> =1.5</p><p></p><p>EQ</p><p>PE</p><p> </p><p> </p><p></p><p>= </p><p>FR</p><p>PF</p><p> </p><p> </p><p></p><p>So, <a href="https://interviewquestions.tuteehub.com/tag/ef-445354" style="font-weight:bold;" target="_blank" title="Click to know more about EF">EF</a> is not parallel to <a href="https://interviewquestions.tuteehub.com/tag/qr-610545" style="font-weight:bold;" target="_blank" title="Click to know more about QR">QR</a>.</p><p></p><p>(<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>) PE=4 cm, QE=4.5 cm, PF=8 cm, RF=9 cm</p><p>Using Basic proportionality theorem,</p><p>∴ </p><p>QE</p><p>PE</p><p> </p><p> = </p><p>4.5</p><p>4</p><p> </p><p> = </p><p>45</p><p>40</p><p> </p><p> = </p><p>9</p><p>8</p><p> </p><p> </p><p></p><p>RF</p><p>PF</p><p> </p><p> = </p><p>9</p><p>8</p><p> </p><p> </p><p></p><p>QE</p><p>PE</p><p> </p><p> = </p><p>RF</p><p>PF</p><p> </p><p> </p><p></p><p>So, EF is parallel to QR.</p><p></p><p>(iii) PQ=1.28 cm, PR=2.56 cm, PE=0.18 cm, PF=0.36 cm </p><p>Using Basic proportionality theorem,</p><p>EQ=PQ−PE=1.28−0.18=1.10 cm</p><p></p><p>FR=PR−PF=2.56−0.36=2.20 cm</p><p></p><p>EQ</p><p>PE</p><p> </p><p> = </p><p>1.10</p><p>0.18</p><p> </p><p> = </p><p>110</p><p>18</p><p> </p><p> = </p><p>55</p><p>9</p><p> </p><p> ... (i)</p><p></p><p>FR</p><p>PE</p><p> </p><p> = </p><p>2.20</p><p>0.36</p><p> </p><p> = </p><p>220</p><p>36</p><p> </p><p> = </p><p>55</p><p>9</p><p> </p><p> ... (ii)</p><p></p><p>∴ </p><p>EQ</p><p>PE</p><p> </p><p> = </p><p>FR.</p><p>PF</p><p> </p><p> </p><p></p><p>So, EF is parallel to QR.</p></body></html>
516.

an athlete completes one round of a circular track of diametre 50 m in 50 s. What will be the distance covered and displacement in 4 min?​

Answer» <html><body><p><strong>Answer:</strong></p><p><a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> :      Diameter of the circular track   D=2R=200  m</p><p></p><p>                  Time     t=2 minutes 20 s  =140  s</p><p></p><p>As the athlete <a href="https://interviewquestions.tuteehub.com/tag/completes-2532986" style="font-weight:bold;" target="_blank" title="Click to know more about COMPLETES">COMPLETES</a> one round in 40 seconds, thus he will be at point B after 140  seconds by covering  three and <a href="https://interviewquestions.tuteehub.com/tag/half-1014510" style="font-weight:bold;" target="_blank" title="Click to know more about HALF">HALF</a>  rounds.</p><p></p><p>∴ Displacement of the athlete       s′=2R=200 m</p><p></p><p>Distance covered     d=3.5×(2πR)</p><p></p><p>d=3.5×722×200=2200   m</p><p></p><p></p><p></p><p></p></body></html>
517.

As water is made of atoms having protons (charge +e) and electrons (charge 2:e), does the water flowing through pipe carry an electric current? Explain.​

Answer» <html><body><p><strong>Answer:</strong></p><p>The net charge on proton is +e. This can be <a href="https://interviewquestions.tuteehub.com/tag/obtained-7273275" style="font-weight:bold;" target="_blank" title="Click to know more about OBTAINED">OBTAINED</a> by p=(32+32−31)e=+e </p><p></p><p>Hence, proton has two 'up' quark and a 'down quark'.</p><p></p><p>The net charge on neutron is <a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>. This can be obtained by <a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>=(32−31−31)=0</p><p></p><p>Hence, neutron has <a href="https://interviewquestions.tuteehub.com/tag/one-585732" style="font-weight:bold;" target="_blank" title="Click to know more about ONE">ONE</a> 'up' quark and two 'down' quarks.</p><p></p><p></p><p></p></body></html>
518.

Four-point charges q1 = 2 micro C, q2 = -5 micro C, q3 = 2 micro C, and q4 = -5 micro Care located add the corners of a square ABCD of side 10 cm. what is the force on a charge of1 micro C placed at the centre of square?​

Answer» <html><body><p></p><p><img align="absmiddle" alt="\underline{\blacksquare\:\:\:\footnotesize{\purple{\textsf{ \textbf{{SOLUTION:-}}}}}}" class="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=%5Cunderline%7B%5Cblacksquare%5C%3A%5C%3A%5C%3A%5Cfootnotesize%7B%5Cpurple%7B%5Ctextsf%7B%20%5Ctextbf%7B%7BSOLUTION%3A-%7D%7D%7D%7D%7D%7D" title="\underline{\blacksquare\:\:\:\footnotesize{\purple{\textsf{ \textbf{{SOLUTION:-}}}}}}"/></p><p></p><p><img align="absmiddle" alt="\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\linethickness{0.5mm}\put(1,1){\line(1,0){6.8}}\end{picture}" class="latex-formula" id="TexFormula2" src="https://tex.z-dn.net/?f=%5Csetlength%7B%5Cunitlength%7D%7B1.0%20cm%7D%7D%5Cbegin%7Bpicture%7D%2812%2C4%29%5Clinethickness%7B0.5mm%7D%5Cput%281%2C1%29%7B%5Cline%281%2C0%29%7B6.8%7D%7D%5Cend%7Bpicture%7D" title="\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\linethickness{0.5mm}\put(1,1){\line(1,0){6.8}}\end{picture}"/></p><p>• Side of square (a) = <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> cm = 0.1 m</p><p>• Five point charges :</p><ol><li>q₁ = 2μC = 2 × 10⁻⁶ C</li><li>q₂ = -5μC = 5 × 10⁻⁶ C</li><li>q₃ = 2μC = 2 × 10⁻⁶ C</li><li>q₄ = -5μC = 5 × 10⁻⁶ C</li><li>q₅ = 1 μC = 1 × 10⁻⁶ C (Point charge present at the <a href="https://interviewquestions.tuteehub.com/tag/centre-912170" style="font-weight:bold;" target="_blank" title="Click to know more about CENTRE">CENTRE</a>)</li></ol><p>• Half of the diagonal of the square = a/√2 = 0.1/√2 m</p><p></p><p><img align="absmiddle" alt="\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\linethickness{0.5mm}\put(1,1){\line(1,0){6.8}}\end{picture}" class="latex-formula" id="TexFormula3" src="https://tex.z-dn.net/?f=%5Csetlength%7B%5Cunitlength%7D%7B1.0%20cm%7D%7D%5Cbegin%7Bpicture%7D%2812%2C4%29%5Clinethickness%7B0.5mm%7D%5Cput%281%2C1%29%7B%5Cline%281%2C0%29%7B6.8%7D%7D%5Cend%7Bpicture%7D" title="\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\linethickness{0.5mm}\put(1,1){\line(1,0){6.8}}\end{picture}"/></p><h3>See the attached <a href="https://interviewquestions.tuteehub.com/tag/figure-987693" style="font-weight:bold;" target="_blank" title="Click to know more about FIGURE">FIGURE</a>!</h3><p>• First of all we will find the <a href="https://interviewquestions.tuteehub.com/tag/electric-967871" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRIC">ELECTRIC</a> field along diagonal AC <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to point charge q₁ = 2μC and q₃ = 2μC.</p><p>• Due to point Charge q₁ = 2μC, the electric field will be away from the centre. </p><p>• Due to point Charge q₃ = 2μC, the electric field will be away from the centre.</p><p></p><p></p><p><img align="absmiddle" alt="\footnotesize{\longrightarrow \rm E_{(AC)}=E_{1} - E_{3} } \\" class="latex-formula" id="TexFormula4" src="https://tex.z-dn.net/?f=%5Cfootnotesize%7B%5Clongrightarrow%20%5Crm%20E_%7B%28AC%29%7D%3DE_%7B1%7D%20-%20E_%7B3%7D%20%7D%20%5C%5C%20" title="\footnotesize{\longrightarrow \rm E_{(AC)}=E_{1} - E_{3} } \\"/></p><p></p><p><img align="absmiddle" alt="\footnotesize{\longrightarrow \rm E_{(AC)}=\dfrac{Kq_{1} }{r^2} - \dfrac{Kq_{3} }{r^2} }" class="latex-formula" id="TexFormula5" src="https://tex.z-dn.net/?f=%5Cfootnotesize%7B%5Clongrightarrow%20%5Crm%20E_%7B%28AC%29%7D%3D%5Cdfrac%7BKq_%7B1%7D%20%7D%7Br%5E2%7D%20%20-%20%20%5Cdfrac%7BKq_%7B3%7D%20%7D%7Br%5E2%7D%20%7D" title="\footnotesize{\longrightarrow \rm E_{(AC)}=\dfrac{Kq_{1} }{r^2} - \dfrac{Kq_{3} }{r^2} }"/></p><p></p><p><img align="absmiddle" alt="\footnotesize{\longrightarrow \rm E_{(AC)}=\dfrac{9 \times {10}^{9} \times 2 \times {10}^{ - 6} }{ \bigg( \frac{0.1}{ \sqrt{2} } \bigg)^{2} } - \dfrac{9 \times {10}^{9} \times 2\times {10}^{ - 6} }{ \bigg(\frac{0.1}{ \sqrt{2} } \bigg)^{2}} }" class="latex-formula" id="TexFormula6" src="https://tex.z-dn.net/?f=%5Cfootnotesize%7B%5Clongrightarrow%20%5Crm%20E_%7B%28AC%29%7D%3D%5Cdfrac%7B9%20%5Ctimes%20%20%7B10%7D%5E%7B9%7D%20%5Ctimes%202%20%5Ctimes%20%20%7B10%7D%5E%7B%20-%206%7D%20%7D%7B%20%5Cbigg%28%20%5Cfrac%7B0.1%7D%7B%20%5Csqrt%7B2%7D%20%7D%20%5Cbigg%29%5E%7B2%7D%20%20%7D%20%20-%20%20%5Cdfrac%7B9%20%5Ctimes%20%20%7B10%7D%5E%7B9%7D%20%5Ctimes%202%5Ctimes%20%20%7B10%7D%5E%7B%20-%206%7D%20%20%7D%7B%20%5Cbigg%28%5Cfrac%7B0.1%7D%7B%20%5Csqrt%7B2%7D%20%7D%20%5Cbigg%29%5E%7B2%7D%7D%20%7D" title="\footnotesize{\longrightarrow \rm E_{(AC)}=\dfrac{9 \times {10}^{9} \times 2 \times {10}^{ - 6} }{ \bigg( \frac{0.1}{ \sqrt{2} } \bigg)^{2} } - \dfrac{9 \times {10}^{9} \times 2\times {10}^{ - 6} }{ \bigg(\frac{0.1}{ \sqrt{2} } \bigg)^{2}} }"/></p><p>• The magnitude of the charges are equal therefore they will cancel each other and electric field along diagonal AC will be 0.</p><p></p><p><img align="absmiddle" alt="\footnotesize{\longrightarrow \underline{ \boxed{ \red{\bf E_{(AC)} = 0 \: N/C}}}}" class="latex-formula" id="TexFormula7" src="https://tex.z-dn.net/?f=%5Cfootnotesize%7B%5Clongrightarrow%20%20%5Cunderline%7B%20%5Cboxed%7B%20%5Cred%7B%5Cbf%20E_%7B%28AC%29%7D%20%3D%200%20%5C%3A%20N%2FC%7D%7D%7D%7D" title="\footnotesize{\longrightarrow \underline{ \boxed{ \red{\bf E_{(AC)} = 0 \: N/C}}}}"/></p><p></p><p><img align="absmiddle" alt="\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\linethickness{0.5mm}\put(1,1){\line(1,0){6.8}}\end{picture}" class="latex-formula" id="TexFormula8" src="https://tex.z-dn.net/?f=%5Csetlength%7B%5Cunitlength%7D%7B1.0%20cm%7D%7D%5Cbegin%7Bpicture%7D%2812%2C4%29%5Clinethickness%7B0.5mm%7D%5Cput%281%2C1%29%7B%5Cline%281%2C0%29%7B6.8%7D%7D%5Cend%7Bpicture%7D" title="\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\linethickness{0.5mm}\put(1,1){\line(1,0){6.8}}\end{picture}"/></p><p>•Now, let's find the electric field along diagonal BD.</p><p>• Due to point charge q₂ = -5μC ,the electric field will be directed towards the centre.</p><p>• Due to point charge q₄ = -5μC, the electric field will be directed towards centre.</p><p>• From the observation we find that the magnitude of the charges are equal therefore they will cancel each other.</p><p>• Hence, electric field along diagonal BD will be 0.</p><p><img align="absmiddle" alt="\footnotesize{\longrightarrow \underline{ \boxed{ \orange{\bf E_{(BD)} = 0 \: N/C}}}}" class="latex-formula" id="TexFormula9" src="https://tex.z-dn.net/?f=%5Cfootnotesize%7B%5Clongrightarrow%20%20%5Cunderline%7B%20%5Cboxed%7B%20%5Corange%7B%5Cbf%20E_%7B%28BD%29%7D%20%3D%200%20%5C%3A%20N%2FC%7D%7D%7D%7D" title="\footnotesize{\longrightarrow \underline{ \boxed{ \orange{\bf E_{(BD)} = 0 \: N/C}}}}"/></p><p><img align="absmiddle" alt="\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\linethickness{0.5mm}\put(1,1){\line(1,0){6.8}}\end{picture}" class="latex-formula" id="TexFormula10" src="https://tex.z-dn.net/?f=%5Csetlength%7B%5Cunitlength%7D%7B1.0%20cm%7D%7D%5Cbegin%7Bpicture%7D%2812%2C4%29%5Clinethickness%7B0.5mm%7D%5Cput%281%2C1%29%7B%5Cline%281%2C0%29%7B6.8%7D%7D%5Cend%7Bpicture%7D" title="\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\linethickness{0.5mm}\put(1,1){\line(1,0){6.8}}\end{picture}"/></p><p>At the centre there are two electric field which are perpendicular to each other, so net electric field can be calculated by using superposition principle:</p><p></p><p><img align="absmiddle" alt="\footnotesize{\longrightarrow \rm E_{(Net)} = \sqrt{E_{(AC)} ^{2} + E_{(BD)}^{2} + 2 E_{(AC)} ^{2} E_{(BD)}^{2} \cos( {90}^{ \circ} ) }} \\" class="latex-formula" id="TexFormula11" src="https://tex.z-dn.net/?f=%5Cfootnotesize%7B%5Clongrightarrow%20%5Crm%20E_%7B%28Net%29%7D%20%3D%20%5Csqrt%7BE_%7B%28AC%29%7D%20%5E%7B2%7D%20%2B%20E_%7B%28BD%29%7D%5E%7B2%7D%20%20%2B%202%20E_%7B%28AC%29%7D%20%5E%7B2%7D%20E_%7B%28BD%29%7D%5E%7B2%7D%20%20%5Ccos%28%20%7B90%7D%5E%7B%20%5Ccirc%7D%20%29%20%7D%7D%20%5C%5C%20" title="\footnotesize{\longrightarrow \rm E_{(Net)} = \sqrt{E_{(AC)} ^{2} + E_{(BD)}^{2} + 2 E_{(AC)} ^{2} E_{(BD)}^{2} \cos( {90}^{ \circ} ) }} \\"/></p><p><img align="absmiddle" alt="\footnotesize{\longrightarrow \rm E_{(Net)} = \sqrt{E_{(AC)} ^{2} + E_{(BD)}^{2} }}" class="latex-formula" id="TexFormula12" src="https://tex.z-dn.net/?f=%5Cfootnotesize%7B%5Clongrightarrow%20%5Crm%20E_%7B%28Net%29%7D%20%3D%20%5Csqrt%7BE_%7B%28AC%29%7D%20%5E%7B2%7D%20%2B%20E_%7B%28BD%29%7D%5E%7B2%7D%20%7D%7D" title="\footnotesize{\longrightarrow \rm E_{(Net)} = \sqrt{E_{(AC)} ^{2} + E_{(BD)}^{2} }}"/></p><p><img align="absmiddle" alt="\footnotesize{\longrightarrow \rm E_{(Net)} =E \sqrt{2 }}" class="latex-formula" id="TexFormula13" src="https://tex.z-dn.net/?f=%5Cfootnotesize%7B%5Clongrightarrow%20%5Crm%20E_%7B%28Net%29%7D%20%3DE%20%5Csqrt%7B2%20%7D%7D" title="\footnotesize{\longrightarrow \rm E_{(Net)} =E \sqrt{2 }}"/></p><p><img align="absmiddle" alt="\footnotesize{\longrightarrow \underline{ \boxed{ \gray{\bf E_{(Net)} =0 \: N/C}}}}" class="latex-formula" id="TexFormula14" src="https://tex.z-dn.net/?f=%5Cfootnotesize%7B%5Clongrightarrow%20%20%5Cunderline%7B%20%5Cboxed%7B%20%5Cgray%7B%5Cbf%20E_%7B%28Net%29%7D%20%3D0%20%5C%3A%20N%2FC%7D%7D%7D%7D" title="\footnotesize{\longrightarrow \underline{ \boxed{ \gray{\bf E_{(Net)} =0 \: N/C}}}}"/></p><p><img align="absmiddle" alt="\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\linethickness{0.5mm}\put(1,1){\line(1,0){6.8}}\end{picture}" class="latex-formula" id="TexFormula15" src="https://tex.z-dn.net/?f=%5Csetlength%7B%5Cunitlength%7D%7B1.0%20cm%7D%7D%5Cbegin%7Bpicture%7D%2812%2C4%29%5Clinethickness%7B0.5mm%7D%5Cput%281%2C1%29%7B%5Cline%281%2C0%29%7B6.8%7D%7D%5Cend%7Bpicture%7D" title="\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\linethickness{0.5mm}\put(1,1){\line(1,0){6.8}}\end{picture}"/></p></body></html>
519.

A ball of mass 150 g is acted upon by a force of 250 dynes for 10 seconds. If the ball is initially at rest, then calculate the final velocity.​

Answer» <html><body><p><strong>Answer:Given that,</strong></p><p><strong></strong></p><p><strong>Force F=100dyn</strong></p><p><strong></strong></p><p><strong>Mass m=5g</strong></p><p><strong></strong></p><p><strong>Time t=10s</strong></p><p><strong></strong></p><p><strong>Initial <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> u=0</strong></p><p><strong></strong></p><p><strong>Now, the acceleration is</strong></p><p><strong></strong></p><p><strong>  F=ma</strong></p><p><strong></strong></p><p><strong> a=  </strong></p><p><strong>m</strong></p><p><strong>F</strong></p><p><strong>​</strong></p><p><strong>  </strong></p><p><strong></strong></p><p><strong> a=  </strong></p><p><strong>5×10  </strong></p><p><strong>−3</strong></p><p><strong>  </strong></p><p><strong>100×10  </strong></p><p><strong>−5</strong></p><p><strong>  </strong></p><p><strong>​</strong></p><p><strong>  </strong></p><p><strong></strong></p><p><strong> a=0.20m/s  </strong></p><p><strong>2</strong></p><p><strong>  </strong></p><p><strong></strong></p><p><strong>Now, from <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a> of motion</strong></p><p><strong></strong></p><p><strong>  v=u+at</strong></p><p><strong></strong></p><p><strong> v=0+0.20×10</strong></p><p><strong></strong></p><p><strong> v=2m/s</strong></p><p><strong></strong></p><p><strong> v=200cm/s</strong></p><p><strong></strong></p><p><strong>Hence, the velocity produced is <a href="https://interviewquestions.tuteehub.com/tag/200-288914" style="font-weight:bold;" target="_blank" title="Click to know more about 200">200</a> cm/s</strong></p><p></p><p><strong>Explanation:</strong></p><p></p></body></html>
520.

Aaj kal koi baat bhi nahi karte, thanks bhi nahi dete, F0LL0W bhi nahi karte.Aisa kya kiya maine ?​

Answer» <html><body><p><strong>Answer:</strong></p><p><a href="https://interviewquestions.tuteehub.com/tag/ok-1127144" style="font-weight:bold;" target="_blank" title="Click to know more about OK">OK</a></p><p><strong>Explanation:</strong></p><p>ok bro <a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a> will give you so <a href="https://interviewquestions.tuteehub.com/tag/much-2164829" style="font-weight:bold;" target="_blank" title="Click to know more about MUCH">MUCH</a> thanks <a href="https://interviewquestions.tuteehub.com/tag/see-630247" style="font-weight:bold;" target="_blank" title="Click to know more about SEE">SEE</a> notifications <a href="https://interviewquestions.tuteehub.com/tag/please-601513" style="font-weight:bold;" target="_blank" title="Click to know more about PLEASE">PLEASE</a> mark me as brainlist</p></body></html>
521.

In the given circuit, B1, B2 and B3 are three bulbs connected with a battery of6 V.(a) What will happen to the glow of the other two bulbs if the bulb B2, gets fused?(b) If the wattage of each bulb is 3 W, what reading will ammeter A show when all the three bulbs glow simultaneously.(c) Find the total resistance of the circuit.​

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><p><a href="https://interviewquestions.tuteehub.com/tag/please-601513" style="font-weight:bold;" target="_blank" title="Click to know more about PLEASE">PLEASE</a> <a href="https://interviewquestions.tuteehub.com/tag/mark-555248" style="font-weight:bold;" target="_blank" title="Click to know more about MARK">MARK</a> as <a href="https://interviewquestions.tuteehub.com/tag/brainlist-2485655" style="font-weight:bold;" target="_blank" title="Click to know more about BRAINLIST">BRAINLIST</a></p></body></html>
522.

Define Displacement ​

Answer» <html><body><p><strong>Explanation:</strong></p><p>Displacement:–The <a href="https://interviewquestions.tuteehub.com/tag/shortest-642834" style="font-weight:bold;" target="_blank" title="Click to know more about SHORTEST">SHORTEST</a> distance between the initial <a href="https://interviewquestions.tuteehub.com/tag/position-1159826" style="font-weight:bold;" target="_blank" title="Click to know more about POSITION">POSITION</a> and the final position of a moving object in the given interval of <a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a> from initial to the final position of the object is <a href="https://interviewquestions.tuteehub.com/tag/known-534098" style="font-weight:bold;" target="_blank" title="Click to know more about KNOWN">KNOWN</a> as the displacement of the object.</p><p></p><p>Hope this helps you ❤️</p><p>pls mark brainlist and follw me</p></body></html>
523.

A Trucks movie with velocity 36 km per hour and gains its speed to 72 km per hour in 5 seconds. Find the acceleration of the truck.a) 20m/s²b) 2m/s²c) 20m/s²d) 0.20m/s²​

Answer» <html><body><p><strong>Answer:</strong></p><p></p><p><strong>Provided</strong><strong> </strong><strong>that</strong><strong>:</strong><strong> </strong></p><ul><li>Initial velocity = 36 kmph</li><li>Final velocity = 72 kmph</li><li>Time = 5 seconds</li></ul><p></p><p><strong>To calculate:</strong></p><ul><li>The acceleration</li></ul><p></p><p><strong>Solution: </strong></p><ul><li>The acceleration = 2 m/s²</li></ul><p></p><p><strong>Using concepts: </strong></p><p></p><p>• We can use either acceleration formula or first <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a> of motion to calculate the acceleration.</p><p></p><p>• Formula to <a href="https://interviewquestions.tuteehub.com/tag/convert-425734" style="font-weight:bold;" target="_blank" title="Click to know more about CONVERT">CONVERT</a> kmph-mps. </p><p></p><p><strong>Using <a href="https://interviewquestions.tuteehub.com/tag/formulas-996894" style="font-weight:bold;" target="_blank" title="Click to know more about FORMULAS">FORMULAS</a>: </strong></p><p></p><p><strong>• Acceleration formula: </strong></p><p></p><ul><li><img align="absmiddle" alt="{\small{\underline{\boxed{\pmb{\sf{a \: = \dfrac{v-u}{t}}}}}}}" class="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=%7B%5Csmall%7B%5Cunderline%7B%5Cboxed%7B%5Cpmb%7B%5Csf%7Ba%20%5C%3A%20%3D%20%5Cdfrac%7Bv-u%7D%7Bt%7D%7D%7D%7D%7D%7D%7D" title="{\small{\underline{\boxed{\pmb{\sf{a \: = \dfrac{v-u}{t}}}}}}}"/> </li></ul><p></p><p><strong>• First equation of motion: </strong></p><p></p><ul><li><img align="absmiddle" alt="{\small{\underline{\boxed{\pmb{\sf{v \: = u \: + at}}}}}}" class="latex-formula" id="TexFormula2" src="https://tex.z-dn.net/?f=%7B%5Csmall%7B%5Cunderline%7B%5Cboxed%7B%5Cpmb%7B%5Csf%7Bv%20%5C%3A%20%3D%20u%20%5C%3A%20%2B%20at%7D%7D%7D%7D%7D%7D" title="{\small{\underline{\boxed{\pmb{\sf{v \: = u \: + at}}}}}}"/> </li></ul><p></p><p><strong>• Formula to convert kmph-mps: </strong></p><p></p><ul><li><img align="absmiddle" alt="{\small{\underline{\boxed{\pmb{\sf{1 \: kmph \: = \dfrac{5}{18} \: mps}}}}}}" class="latex-formula" id="TexFormula3" src="https://tex.z-dn.net/?f=%7B%5Csmall%7B%5Cunderline%7B%5Cboxed%7B%5Cpmb%7B%5Csf%7B1%20%5C%3A%20kmph%20%5C%3A%20%3D%20%5Cdfrac%7B5%7D%7B18%7D%20%5C%3A%20mps%7D%7D%7D%7D%7D%7D" title="{\small{\underline{\boxed{\pmb{\sf{1 \: kmph \: = \dfrac{5}{18} \: mps}}}}}}"/> </li></ul><p></p><p>Where, <strong>a</strong> <a href="https://interviewquestions.tuteehub.com/tag/denotes-948116" style="font-weight:bold;" target="_blank" title="Click to know more about DENOTES">DENOTES</a> acceleration, <strong>u</strong> denotes initial velocity, <strong>v</strong> denotes final velocity, <strong>t</strong> denotes time taken. </p><p></p><p><strong>Required solution: </strong></p><p></p><p><strong>~</strong> Firstly let us convert kmph-mps!</p><p></p><p><em>Converting 72 kmph-mps.</em></p><p></p><p><img align="absmiddle" alt=":\implies \sf 72 \times \dfrac{5}{18} \\ \\ :\implies \sf \cancel{72} \times \dfrac{5}{\cancel{{18}}} \: (Cancelling) \\ \\ :\implies \sf 4 \times 5 \\ \\ :\implies \sf 20 \: mps \\ \\ {\pmb{\sf{Henceforth, \: converted!}}}" class="latex-formula" id="TexFormula4" src="https://tex.z-dn.net/?f=%3A%5Cimplies%20%5Csf%2072%20%5Ctimes%20%5Cdfrac%7B5%7D%7B18%7D%20%5C%5C%20%5C%5C%20%3A%5Cimplies%20%5Csf%20%5Ccancel%7B72%7D%20%5Ctimes%20%5Cdfrac%7B5%7D%7B%5Ccancel%7B%7B18%7D%7D%7D%20%5C%3A%20%28Cancelling%29%20%5C%5C%20%5C%5C%20%3A%5Cimplies%20%5Csf%204%20%5Ctimes%205%20%5C%5C%20%5C%5C%20%3A%5Cimplies%20%5Csf%2020%20%5C%3A%20mps%20%5C%5C%20%5C%5C%20%7B%5Cpmb%7B%5Csf%7BHenceforth%2C%20%5C%3A%20converted%21%7D%7D%7D" title=":\implies \sf 72 \times \dfrac{5}{18} \\ \\ :\implies \sf \cancel{72} \times \dfrac{5}{\cancel{{18}}} \: (Cancelling) \\ \\ :\implies \sf 4 \times 5 \\ \\ :\implies \sf 20 \: mps \\ \\ {\pmb{\sf{Henceforth, \: converted!}}}"/> </p><p></p><p><em>Converting 36 kmph-mps.</em></p><p></p><p><img align="absmiddle" alt=":\implies \sf 36 \times \dfrac{5}{18} \\ \\ :\implies \sf \cancel{36} \times \dfrac{5}{\cancel{{18}}} \: (Cancelling) \\ \\ :\implies \sf 2 \times 5 \\ \\ :\implies \sf 10 \: mps \\ \\ {\pmb{\sf{Henceforth, \: converted!}}}" class="latex-formula" id="TexFormula5" src="https://tex.z-dn.net/?f=%3A%5Cimplies%20%5Csf%2036%20%5Ctimes%20%5Cdfrac%7B5%7D%7B18%7D%20%5C%5C%20%5C%5C%20%3A%5Cimplies%20%5Csf%20%5Ccancel%7B36%7D%20%5Ctimes%20%5Cdfrac%7B5%7D%7B%5Ccancel%7B%7B18%7D%7D%7D%20%5C%3A%20%28Cancelling%29%20%5C%5C%20%5C%5C%20%3A%5Cimplies%20%5Csf%202%20%5Ctimes%205%20%5C%5C%20%5C%5C%20%3A%5Cimplies%20%5Csf%2010%20%5C%3A%20mps%20%5C%5C%20%5C%5C%20%7B%5Cpmb%7B%5Csf%7BHenceforth%2C%20%5C%3A%20converted%21%7D%7D%7D" title=":\implies \sf 36 \times \dfrac{5}{18} \\ \\ :\implies \sf \cancel{36} \times \dfrac{5}{\cancel{{18}}} \: (Cancelling) \\ \\ :\implies \sf 2 \times 5 \\ \\ :\implies \sf 10 \: mps \\ \\ {\pmb{\sf{Henceforth, \: converted!}}}"/> </p><p> </p><p>Therefore,</p><ul><li>Initial velocity = 10 mps</li><li>Final velocity = 20 mps</li></ul><p></p><p><strong>~</strong> Now let's <a href="https://interviewquestions.tuteehub.com/tag/find-11616" style="font-weight:bold;" target="_blank" title="Click to know more about FIND">FIND</a> out the acceleration! </p><p></p><p><em>By using acceleration formula.</em></p><p></p><p><img align="absmiddle" alt=":\implies \sf a \: = \dfrac{v-u}{t} \\ \\ :\implies \sf a \: = \dfrac{20 - 10}{5} \\ \\ :\implies \sf a \: = \dfrac{10}{5} \\ \\ :\implies \sf a \: = 2 \: ms^{-2} \\ \\ :\implies \sf Acceleration \: = 2 \: ms^{-2}" class="latex-formula" id="TexFormula6" src="https://tex.z-dn.net/?f=%3A%5Cimplies%20%5Csf%20a%20%5C%3A%20%3D%20%5Cdfrac%7Bv-u%7D%7Bt%7D%20%5C%5C%20%5C%5C%20%3A%5Cimplies%20%5Csf%20a%20%5C%3A%20%3D%20%5Cdfrac%7B20%20-%2010%7D%7B5%7D%20%5C%5C%20%5C%5C%20%3A%5Cimplies%20%5Csf%20a%20%5C%3A%20%3D%20%5Cdfrac%7B10%7D%7B5%7D%20%5C%5C%20%5C%5C%20%3A%5Cimplies%20%5Csf%20a%20%5C%3A%20%3D%202%20%20%5C%3A%20ms%5E%7B-2%7D%20%5C%5C%20%5C%5C%20%3A%5Cimplies%20%5Csf%20Acceleration%20%5C%3A%20%3D%202%20%5C%3A%20ms%5E%7B-2%7D" title=":\implies \sf a \: = \dfrac{v-u}{t} \\ \\ :\implies \sf a \: = \dfrac{20 - 10}{5} \\ \\ :\implies \sf a \: = \dfrac{10}{5} \\ \\ :\implies \sf a \: = 2 \: ms^{-2} \\ \\ :\implies \sf Acceleration \: = 2 \: ms^{-2}"/> </p><p></p><p><em>By using first equation of motion. </em></p><p></p><p><img align="absmiddle" alt=":\implies \sf v \: = u \: + at \\ \\ :\implies \sf 20 = 10 + a(5) \\ \\ :\implies \sf 20 - 10 = 5a \\ \\ :\implies \sf 10 = 5a \\ \\ :\implies \sf a \: = \dfrac{10}{5} \\ \\ :\implies \sf a \: = 2 \: ms^{-2} \\ \\ :\implies \sf Acceleration \: = 2 \: ms^{-2}" class="latex-formula" id="TexFormula7" src="https://tex.z-dn.net/?f=%3A%5Cimplies%20%5Csf%20v%20%5C%3A%20%3D%20u%20%5C%3A%20%2B%20at%20%5C%5C%20%5C%5C%20%3A%5Cimplies%20%5Csf%2020%20%3D%2010%20%2B%20a%285%29%20%5C%5C%20%5C%5C%20%3A%5Cimplies%20%5Csf%2020%20-%2010%20%3D%205a%20%5C%5C%20%5C%5C%20%3A%5Cimplies%20%5Csf%2010%20%3D%205a%20%5C%5C%20%5C%5C%20%3A%5Cimplies%20%5Csf%20a%20%5C%3A%20%3D%20%5Cdfrac%7B10%7D%7B5%7D%20%5C%5C%20%5C%5C%20%3A%5Cimplies%20%5Csf%20a%20%5C%3A%20%3D%202%20%5C%3A%20ms%5E%7B-2%7D%20%5C%5C%20%5C%5C%20%3A%5Cimplies%20%5Csf%20Acceleration%20%5C%3A%20%3D%202%20%5C%3A%20ms%5E%7B-2%7D" title=":\implies \sf v \: = u \: + at \\ \\ :\implies \sf 20 = 10 + a(5) \\ \\ :\implies \sf 20 - 10 = 5a \\ \\ :\implies \sf 10 = 5a \\ \\ :\implies \sf a \: = \dfrac{10}{5} \\ \\ :\implies \sf a \: = 2 \: ms^{-2} \\ \\ :\implies \sf Acceleration \: = 2 \: ms^{-2}"/></p></body></html>
524.

The capacity of isolated conducting charge sphere of radius r is propertional to​

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><p><a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> <a href="https://interviewquestions.tuteehub.com/tag/chorus-419311" style="font-weight:bold;" target="_blank" title="Click to know more about CHORUS">CHORUS</a> okkkkkkkkkkkkkkkkkkk</p></body></html>
525.

the resultant resistance of a circuit where 10ohm, 20ohm, 30ohm, and 40ohm, are connected in parallel

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><p><a href="https://interviewquestions.tuteehub.com/tag/rp-625933" style="font-weight:bold;" target="_blank" title="Click to know more about RP">RP</a>= 5.45 <a href="https://interviewquestions.tuteehub.com/tag/ohm-1129796" style="font-weight:bold;" target="_blank" title="Click to know more about OHM">OHM</a></p><p><strong>Explanation:</strong></p><p><strong><a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>/Rp = 1/R1 + 1/R2 + 1/R3</strong></p><p><strong>1/Rp = 1/10 + 1/20 + 1/30</strong></p><p><strong>1/Rp = 0.1833</strong></p><p>Rp= 1/ 0.18333</p><p>Rp = 5.45 Ohm</p></body></html>
526.

Explain giving two examples to show that inertia of a body changes due to change in its mass.

Answer» <html><body><p><strong>Answer:</strong></p><p>mark me as brainliest </p><p><strong>Explanation:</strong></p><p><a href="https://interviewquestions.tuteehub.com/tag/objects-20533" style="font-weight:bold;" target="_blank" title="Click to know more about OBJECTS">OBJECTS</a> want to <a href="https://interviewquestions.tuteehub.com/tag/stay-1226662" style="font-weight:bold;" target="_blank" title="Click to know more about STAY">STAY</a> in rest or <a href="https://interviewquestions.tuteehub.com/tag/motion-1104108" style="font-weight:bold;" target="_blank" title="Click to know more about MOTION">MOTION</a> unless an outside force causes a change. For example, if you roll a <a href="https://interviewquestions.tuteehub.com/tag/ball-891849" style="font-weight:bold;" target="_blank" title="Click to know more about BALL">BALL</a>, it will continue rolling unless friction or something else stops it by force. You can also think about the <a href="https://interviewquestions.tuteehub.com/tag/way-1450548" style="font-weight:bold;" target="_blank" title="Click to know more about WAY">WAY</a> that your body keeps moving forward when you hit the brake on your bike.</p></body></html>
527.

16 একটি জলের ট্যাংকের দৈর্ঘ্য, প্রস্থ ও উচ্চতা যথাক্রমে 3m, 2m ও 1m। ট্যাংকটি অর্ধেক জলপূর্ণ। ট্যাংকের জলের আয়তন হল- A 6000 L ৪) 30000 L C 3000 L D 6000​

Answer» <html><body><p><strong>Answer:</strong></p><p><a href="https://interviewquestions.tuteehub.com/tag/hello-484176" style="font-weight:bold;" target="_blank" title="Click to know more about HELLO">HELLO</a> <a href="https://interviewquestions.tuteehub.com/tag/friend-458332" style="font-weight:bold;" target="_blank" title="Click to know more about FRIEND">FRIEND</a> </p><p><a href="https://interviewquestions.tuteehub.com/tag/good-1009017" style="font-weight:bold;" target="_blank" title="Click to know more about GOOD">GOOD</a> morning</p><p>have a great day</p></body></html>
528.

Reactance depends on

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a>:</strong></p><p>As the frequency <a href="https://interviewquestions.tuteehub.com/tag/approaches-882352" style="font-weight:bold;" target="_blank" title="Click to know more about APPROACHES">APPROACHES</a> infinity the inductors reactance would also increase to infinity <a href="https://interviewquestions.tuteehub.com/tag/acting-269" style="font-weight:bold;" target="_blank" title="Click to know more about ACTING">ACTING</a> like an open <a href="https://interviewquestions.tuteehub.com/tag/circuit-916593" style="font-weight:bold;" target="_blank" title="Click to know more about CIRCUIT">CIRCUIT</a>. However, as the frequency approaches zero or DC, the inductors reactance would decrease to zero, acting like a <a href="https://interviewquestions.tuteehub.com/tag/short-642706" style="font-weight:bold;" target="_blank" title="Click to know more about SHORT">SHORT</a> circuit. This means then that inductive reactance is “proportional” to frequency.</p></body></html>
529.

The refractive index of transparent medium is equal to __________​

Answer» <html><body><p><strong>Answer:</strong></p><p>1 <a href="https://interviewquestions.tuteehub.com/tag/one-585732" style="font-weight:bold;" target="_blank" title="Click to know more about ONE">ONE</a> </p><p></p><p>Transparent medium become invisible in vacuum if its refractive index becomes <a href="https://interviewquestions.tuteehub.com/tag/equal-446400" style="font-weight:bold;" target="_blank" title="Click to know more about EQUAL">EQUAL</a> to 1, since refractive index of vacuum is also unity because of which refraction of light will not <a href="https://interviewquestions.tuteehub.com/tag/take-662846" style="font-weight:bold;" target="_blank" title="Click to know more about TAKE">TAKE</a> <a href="https://interviewquestions.tuteehub.com/tag/place-1155224" style="font-weight:bold;" target="_blank" title="Click to know more about PLACE">PLACE</a> in the transparent medium.</p><p><strong>Explanation:</strong></p><p><a href="https://interviewquestions.tuteehub.com/tag/please-601513" style="font-weight:bold;" target="_blank" title="Click to know more about PLEASE">PLEASE</a> mark me as brainlist</p></body></html>
530.

A student performs an experiment on measuring friction forces in different trials. For trial A, she pulls a wooden block across a horizontal surface with a constant speeD) For trial B, she inclines the same surface at angle ? with respect to the horizontal. Which of the following is true about the friction force between the block and the surface?​

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><p>For trial</p><p></p><p>hope it's <a href="https://interviewquestions.tuteehub.com/tag/help-1018089" style="font-weight:bold;" target="_blank" title="Click to know more about HELP">HELP</a> you!!!</p></body></html>
531.

If there is an attractive force between all objects, why do we not feel ourselves gravitating towardmassive buildings in our vicinity?

Answer» <html><body><p><strong>Explanation:</strong></p><p>Gravitational force is a weak force unless large masses are involved. The masses of <a href="https://interviewquestions.tuteehub.com/tag/humans-1033536" style="font-weight:bold;" target="_blank" title="Click to know more about HUMANS">HUMANS</a> are quite small and thus the magnitude of gravitational force is also very small and negligible as compared to that <a href="https://interviewquestions.tuteehub.com/tag/shown-1206565" style="font-weight:bold;" target="_blank" title="Click to know more about SHOWN">SHOWN</a> by Earth. Thus, gravitational force exists between <a href="https://interviewquestions.tuteehub.com/tag/two-714195" style="font-weight:bold;" target="_blank" title="Click to know more about TWO">TWO</a> people sitting <a href="https://interviewquestions.tuteehub.com/tag/close-408965" style="font-weight:bold;" target="_blank" title="Click to know more about CLOSE">CLOSE</a> by but it is negligible and cannot be felt.</p></body></html>
532.

The velocity of the car is 15 m/sec and the acceleration is zero.how can you express such situation ?

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><p></p><p><strong><a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a>:</strong></p><p><a href="https://interviewquestions.tuteehub.com/tag/easy-444822" style="font-weight:bold;" target="_blank" title="Click to know more about EASY">EASY</a></p></body></html>
533.

Find in supeepotion theroem2.mesh and nodal analysis.​

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><p>what is the answer <a href="https://interviewquestions.tuteehub.com/tag/tell-1240910" style="font-weight:bold;" target="_blank" title="Click to know more about TELL">TELL</a> <a href="https://interviewquestions.tuteehub.com/tag/us-718298" style="font-weight:bold;" target="_blank" title="Click to know more about US">US</a> </p></body></html>
534.

Accuracy of the value 26.4 mm isa) 0,1mm b) 0,01cm c) Both (a) and (b) d) None of these​

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><p>d) none of the above </p><p><strong><a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a>:</strong></p><p>as the above <a href="https://interviewquestions.tuteehub.com/tag/mentioned-1093838" style="font-weight:bold;" target="_blank" title="Click to know more about MENTIONED">MENTIONED</a> value is not equal to 26.4mm and if we <a href="https://interviewquestions.tuteehub.com/tag/convert-425734" style="font-weight:bold;" target="_blank" title="Click to know more about CONVERT">CONVERT</a> it into cm then 2.6 cm is your answer so d is <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> </p></body></html>
535.

Solve this question and plz explain this question​

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><p>don't <a href="https://interviewquestions.tuteehub.com/tag/know-534065" style="font-weight:bold;" target="_blank" title="Click to know more about KNOW">KNOW</a> sooooorrrrrrrrrrryyyyyyyyyy</p></body></html>
536.

1. An object is placed 20 cm from (a) a converging lens, & (b) a diverging lens, of focal length 15 cm. Calculate the image position and magnification in each case.2. A 2.0 cm tall object is placed 40 cm from a diverging lens of focal length 15 cm. Find the position and size of the image. Solve this questions. Whoever will answer my questions ?Thank "U"In Return, Your answers will be gonna rain of thanks ✨Have a nice day,Stay safe happy & healthy to everyone. ​

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/please-601513" style="font-weight:bold;" target="_blank" title="Click to know more about PLEASE">PLEASE</a></strong><strong> </strong><strong>see</strong><strong> </strong><strong>the</strong><strong> </strong><strong>attachment</strong><strong>.</strong></p><p><strong>Hope</strong><strong> </strong><strong>it</strong><strong> </strong><strong>helps</strong><strong> </strong><strong>u</strong><strong> </strong><strong></strong><strong> </strong><strong>my</strong><strong> </strong><strong><a href="https://interviewquestions.tuteehub.com/tag/dear-431391" style="font-weight:bold;" target="_blank" title="Click to know more about DEAR">DEAR</a></strong><strong> </strong><strong></strong><strong> </strong><strong>di</strong><strong>.</strong></p><p><strong>God</strong><strong> </strong><strong>bless</strong><strong> </strong><strong>you</strong><strong> </strong><strong>and</strong><strong> </strong><strong>your</strong><strong> </strong><strong>family</strong><strong> </strong><strong>and</strong><strong> </strong><strong><a href="https://interviewquestions.tuteehub.com/tag/friends-466025" style="font-weight:bold;" target="_blank" title="Click to know more about FRIENDS">FRIENDS</a></strong><strong>.</strong></p><p></p><p></p><p></p><p></p><p></p><p></p><p></p><p></p><p></p><p><img align="absmiddle" alt="genius \: girl" class="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=genius%20%5C%3A%20girl" title="genius \: girl"/><strong></strong></p><p></p></body></html>
537.

What are protons ?.... ...Mai to sanskari huclass bunk ni marta... ​

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><p>Protons are the <a href="https://interviewquestions.tuteehub.com/tag/positively-7259849" style="font-weight:bold;" target="_blank" title="Click to know more about POSITIVELY">POSITIVELY</a> <a href="https://interviewquestions.tuteehub.com/tag/charged-7263949" style="font-weight:bold;" target="_blank" title="Click to know more about CHARGED">CHARGED</a> particles which are present in the nucleus of a <a href="https://interviewquestions.tuteehub.com/tag/hydrogen-22331" style="font-weight:bold;" target="_blank" title="Click to know more about HYDROGEN">HYDROGEN</a> atom. ..</p><p><strong>Explanation:</strong></p><p></p></body></html>
538.

Accuracy of the value 26.4 mm is . a) 0,1mm b) 0,01cm c) Both (a) and (b) d) None of these​

Answer» <html><body><p><strong>Answer:</strong></p><p>d <a href="https://interviewquestions.tuteehub.com/tag/none-580659" style="font-weight:bold;" target="_blank" title="Click to know more about NONE">NONE</a> of the above </p><p><strong><a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a>:</strong></p><p>as when we <a href="https://interviewquestions.tuteehub.com/tag/convert-425734" style="font-weight:bold;" target="_blank" title="Click to know more about CONVERT">CONVERT</a> 26.4mm into <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a> then the answer will be 2.6cm which is not <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> so d is correct </p></body></html>
539.

'किनशिप ऑर्गेनाइजेशन इन इण्डिया' नामक पुस्तक के लेखक कौन हैं? ऑब्जेक्ट​

Answer» <html><body><p>This is not <a href="https://interviewquestions.tuteehub.com/tag/physics-352" style="font-weight:bold;" target="_blank" title="Click to know more about PHYSICS">PHYSICS</a> this is <a href="https://interviewquestions.tuteehub.com/tag/hindi-1684" style="font-weight:bold;" target="_blank" title="Click to know more about HINDI">HINDI</a></p></body></html>
540.

What id the full form of dav​

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><p>Dayanand <a href="https://interviewquestions.tuteehub.com/tag/anglo-378251" style="font-weight:bold;" target="_blank" title="Click to know more about ANGLO">ANGLO</a> <a href="https://interviewquestions.tuteehub.com/tag/vedic-725594" style="font-weight:bold;" target="_blank" title="Click to know more about VEDIC">VEDIC</a> (DAV)</p><p><strong>Explanation:</strong></p><p><a href="https://interviewquestions.tuteehub.com/tag/mark-555248" style="font-weight:bold;" target="_blank" title="Click to know more about MARK">MARK</a> me as <a href="https://interviewquestions.tuteehub.com/tag/brainliest-1995348" style="font-weight:bold;" target="_blank" title="Click to know more about BRAINLIEST">BRAINLIEST</a></p></body></html>
541.

Friction opposes the____ between the surface in contact with eachother.​

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><p><a href="https://interviewquestions.tuteehub.com/tag/movement-1104563" style="font-weight:bold;" target="_blank" title="Click to know more about MOVEMENT">MOVEMENT</a>...</p><p><strong><a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a>:</strong></p><p><a href="https://interviewquestions.tuteehub.com/tag/hope-25911" style="font-weight:bold;" target="_blank" title="Click to know more about HOPE">HOPE</a> it <a href="https://interviewquestions.tuteehub.com/tag/helps-1018140" style="font-weight:bold;" target="_blank" title="Click to know more about HELPS">HELPS</a></p></body></html>
542.

A ball is thrown vertically upward with a velocity of 98 metre per second how high does the ball rise ​

Answer» <html><body><p><strong>Answer:xf=xi + vi(t) + (at^2)/2</strong></p><p><strong></strong></p><p><strong>Make the vertical axis the x-axis. <a href="https://interviewquestions.tuteehub.com/tag/could-410026" style="font-weight:bold;" target="_blank" title="Click to know more about COULD">COULD</a> have <a href="https://interviewquestions.tuteehub.com/tag/used-2318798" style="font-weight:bold;" target="_blank" title="Click to know more about USED">USED</a> y, but I don't want to retype the formula.</strong></p><p><strong></strong></p><p><strong>xf= <a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a> + 98(t) -4.9t^2</strong></p><p><strong></strong></p><p><strong>vf= vi + at ….the ball is projected up. Once the ball leaves the cannon, only gravity and air resistance act <a href="https://interviewquestions.tuteehub.com/tag/upon-2315586" style="font-weight:bold;" target="_blank" title="Click to know more about UPON">UPON</a> it. We’re neglecting air resistance, so we’re considering only gravity. As the ball rises it continues to decelerate until it reaches its maximum height, at which point it momentarily stops, and its velocity is zero. So, vf = 0. We couldn't make this assumption if the ball was dropped, since we don't know its velocity when it hits the ground.</strong></p><p><strong></strong></p><p><strong>0 = 98 - 9.81(t)</strong></p><p><strong></strong></p><p><strong>t= 10 s</strong></p><p><strong></strong></p><p><strong>xf = 980 -490 = 490m This is the maximum height.</strong></p><p></p><p><strong>Explanation:</strong></p><p></p></body></html>
543.

Solve this questionthis question​

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><p><a href="https://interviewquestions.tuteehub.com/tag/pic-591410" style="font-weight:bold;" target="_blank" title="Click to know more about PIC">PIC</a> not <a href="https://interviewquestions.tuteehub.com/tag/clear-408920" style="font-weight:bold;" target="_blank" title="Click to know more about CLEAR">CLEAR</a></p><p>make <a href="https://interviewquestions.tuteehub.com/tag/sure-656539" style="font-weight:bold;" target="_blank" title="Click to know more about SURE">SURE</a> that <a href="https://interviewquestions.tuteehub.com/tag/ur-721789" style="font-weight:bold;" target="_blank" title="Click to know more about UR">UR</a> pic is clear</p></body></html>
544.

A boy travels a 3 km road stops and comes back at center? What will be the distance and displacement?​

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><p></p><h3><em>●</em><em> </em><em>Distance</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>boy</em><em> </em><em>=</em><em> </em><em>6</em><em> </em><em>km</em><em>.</em></h3><h3><em>●</em><em> </em><em>Displacement</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>boy</em><em> </em><em>=</em><em> </em><em>0</em><em> </em><em>km</em><em>.</em></h3><p></p><p><strong>Explanation:</strong></p><p></p><p>A boy travels a distance of 3km then stops and <a href="https://interviewquestions.tuteehub.com/tag/comes-2017383" style="font-weight:bold;" target="_blank" title="Click to know more about COMES">COMES</a> back to the point from where he <a href="https://interviewquestions.tuteehub.com/tag/starts-1224822" style="font-weight:bold;" target="_blank" title="Click to know more about STARTS">STARTS</a> travelling.</p><p></p><p>☆ Total Distance covered by the boy.</p><p> = 2 × 3 km.</p><p> = 6 km.</p><p></p><p>☆ Displacement of the boy = 0 km.</p><p></p><p>= <em>(</em><em> </em><em>Because</em><em> </em><em><a href="https://interviewquestions.tuteehub.com/tag/initial-499269" style="font-weight:bold;" target="_blank" title="Click to know more about INITIAL">INITIAL</a></em><em> </em><em>position</em><em> </em><em>and</em><em> </em><em>the</em><em> </em><em><a href="https://interviewquestions.tuteehub.com/tag/final-461168" style="font-weight:bold;" target="_blank" title="Click to know more about FINAL">FINAL</a></em><em> </em><em>position</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>boy</em><em> </em><em>is</em><em> </em><em>same</em><em> </em><em>)</em><em> </em><em>.</em></p></body></html>
545.

A body thrown up vertically with a velocity of 19.6 ms-1. Find the maximum height reached and time of ascent. ​

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><p>A <a href="https://interviewquestions.tuteehub.com/tag/body-900196" style="font-weight:bold;" target="_blank" title="Click to know more about BODY">BODY</a> <a href="https://interviewquestions.tuteehub.com/tag/projected-1169295" style="font-weight:bold;" target="_blank" title="Click to know more about PROJECTED">PROJECTED</a> <a href="https://interviewquestions.tuteehub.com/tag/vertically-3260386" style="font-weight:bold;" target="_blank" title="Click to know more about VERTICALLY">VERTICALLY</a> upwards with a velocity of 19.6ms−1 reaches a <a href="https://interviewquestions.tuteehub.com/tag/height-1017806" style="font-weight:bold;" target="_blank" title="Click to know more about HEIGHT">HEIGHT</a> of 19.6m on earth. If it is projected vertically up with the same velocity on moon, then the maximum height reached by it is (gearth=g ms−2, gmoon=6g ms−2)</p><p></p><p></p></body></html>
546.

3. From a rifle of mass 4 kg, a bullet of mass 50 g is fired with an initial velocity of 35 m s^-1. Calculate the initial recoil velocity of the rifle.​

Answer» <html><body><p><strong>Answer:</strong></p><p>63kg</p><p></p><p>hope it's <a href="https://interviewquestions.tuteehub.com/tag/help-1018089" style="font-weight:bold;" target="_blank" title="Click to know more about HELP">HELP</a> you!!!</p></body></html>
547.

Find the maximum velocity for slipping a car moving on a circular track of radius 100m. The coefficient of friction between the road and tire is 0.2:A. 0.14m/sB. 140 m/s C.1.4km/s D. 14m/s​

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><p><a href="https://interviewquestions.tuteehub.com/tag/nope-3748435" style="font-weight:bold;" target="_blank" title="Click to know more about NOPE">NOPE</a> <a href="https://interviewquestions.tuteehub.com/tag/hope-25911" style="font-weight:bold;" target="_blank" title="Click to know more about HOPE">HOPE</a> <a href="https://interviewquestions.tuteehub.com/tag/dope-958411" style="font-weight:bold;" target="_blank" title="Click to know more about DOPE">DOPE</a> <a href="https://interviewquestions.tuteehub.com/tag/bro-391138" style="font-weight:bold;" target="_blank" title="Click to know more about BRO">BRO</a> i don't</p></body></html>
548.

What is the net force​

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><p>Net force is the vector sum of forces acting on a <a href="https://interviewquestions.tuteehub.com/tag/particle-1147478" style="font-weight:bold;" target="_blank" title="Click to know more about PARTICLE">PARTICLE</a> or body. The net force is a single force that replaces the <a href="https://interviewquestions.tuteehub.com/tag/effect-966056" style="font-weight:bold;" target="_blank" title="Click to know more about EFFECT">EFFECT</a> of the <a href="https://interviewquestions.tuteehub.com/tag/original-1139424" style="font-weight:bold;" target="_blank" title="Click to know more about ORIGINAL">ORIGINAL</a> forces on the particle's motion. It gives the particle the same acceleration as all those actual forces together as <a href="https://interviewquestions.tuteehub.com/tag/described-7260580" style="font-weight:bold;" target="_blank" title="Click to know more about DESCRIBED">DESCRIBED</a> by Newton's second law of motion</p><p></p><p></p></body></html>
549.

Is there someone who knows physics and can help me with some questions ?

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><p>okaayyyyyy</p><p><strong>Explanation:</strong></p><p>okayyyyyyyyyyyyyyyyyyyy</p></body></html>
550.

Use the data in Table 12.2 (in NCERT Book on Page No. 207) to answer the following : (i) Which among iron and mercury is a better conductor ? (ii) Which material is the best conductor ?​

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a>:</strong></p><p>(1) <a href="https://interviewquestions.tuteehub.com/tag/iron-1051344" style="font-weight:bold;" target="_blank" title="Click to know more about IRON">IRON</a> </p><p>(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) silver is best conductor</p></body></html>