0.00050 mole of NaHCO_(3) is added to a large volume of a solution buffer at pH = 8.00. How much material will exist in each of the three forms, H_(2)CO_(3), HCO_(3)^(-) and CO_(3)^(2-) ? K_(1) and K_(2) for H_(2)CO_(3) are 4.5xx10^(-7) and 4.5xx10^(-11) respectively.

0.00050 mole of NaHCO_(3) is added to a large volume of a solution buf

1.	0.00050 mole of NaHCO_(3) is added to a large volume of a solution buffer at pH = 8.00. How much material will exist in each of the three forms, H_(2)CO_(3), HCO_(3)^(-) and CO_(3)^(2-) ? K_(1) and K_(2) for H_(2)CO_(3) are 4.5xx10^(-7) and 4.5xx10^(-11) respectively.
Answer» <html><body><p><br/></p>Answer :`n_(H_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)CO_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>))= 1.069xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>), n_(HCO_(3)^(-))= <a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>.86xx10^(-4)`, <br/> `n_(CO_(3)^(2-))= 2.28xx10^(-6)`;</body></html>