Saved Bookmarks
| 1. |
0.002 M kOH calculate pH |
|
Answer» (d) 0.002 M KOH [OH-] = [KOH] [OH-] = 0.002 pOH = - LOG [OH-] =-log[0.002] = 2.69 pH= 14-2.69 = 11.70 |
|