0.002 M potassium thiocyanate added to 1 mL 0.2 M Fe (III) nitrate tha

1.	0.002 M potassium thiocyanate added to 1 mL 0.2 M Fe (III) nitrate than what happen ?
Answer» <html><body><p></p>Solution :The iron (III) Nitrate `Fe^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>+)` is react with potassium thiocyanate `SCN^-` and <a href="https://interviewquestions.tuteehub.com/tag/form-996208" style="font-weight:bold;" target="_blank" title="Click to know more about FORM">FORM</a> `[Fe(SCN)]_((aq))^(2+)` and <a href="https://interviewquestions.tuteehub.com/tag/following-463335" style="font-weight:bold;" target="_blank" title="Click to know more about FOLLOWING">FOLLOWING</a> equilibrium is established. The solution is red because the ferric thiocyanate <a href="https://interviewquestions.tuteehub.com/tag/ion-1051153" style="font-weight:bold;" target="_blank" title="Click to know more about ION">ION</a> is red.<br/>`Fe_((aq))^(3+) + SCN_((aq))^(-) hArr <a href="https://interviewquestions.tuteehub.com/tag/underset-3243992" style="font-weight:bold;" target="_blank" title="Click to know more about UNDERSET">UNDERSET</a>"dark red"(`[Fe(SCN)]_((aq))^(2+))`</body></html>

0.002 M potassium thiocyanate added to 1 mL 0.2 M Fe (III) nitrate than what happen ?