0.002 M potassium thiocyanate added to 1 mL 0.2 M Fe (III) nitrate tha

1.	0.002 M potassium thiocyanate added to 1 mL 0.2 M Fe (III) nitrate than what happen ?
Answer» Solution :The iron (III) Nitrate `Fe^(3+)` is react with potassium thiocyanate `SCN^-` and FORM `[Fe(SCN)]_((aq))^(2+)` and FOLLOWING equilibrium is established. The solution is red because the ferric thiocyanate ION is red. `Fe_((aq))^(3+) + SCN_((aq))^(-) hArr UNDERSET"dark red"(`[Fe(SCN)]_((aq))^(2+))`

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