0.004 gof NaOHis present in 1Lof a solution. The pH of the solution is

1.	0.004 gof NaOHis present in 1Lof a solution. The pH of the solution is
Answer» `14.0` ` 12.0` ` 10.0` ` 8.0 ` Solution :`N= (0.004) /(40 ) = 10 ^(-4),V =1L ` ` therefore [OH^(-) ] =(10 ^(-4))/( 1) = 10 ^(-4)` ` thereforePOH = 4 rArr pH = 14- 4 = 10 `

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