0.004 gof NaOHis present in 1Lof a solution. The pH of the solution is

1.	0.004 gof NaOHis present in 1Lof a solution. The pH of the solution is
Answer» <html><body><p>`14.0` <br/>` 12.0` <br/>` 10.0` <br/>` 8.0 ` </p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>= (0.004) /(<a href="https://interviewquestions.tuteehub.com/tag/40-314386" style="font-weight:bold;" target="_blank" title="Click to know more about 40">40</a> ) = 10 ^(-4),<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a> =1L ` <br/> ` therefore [<a href="https://interviewquestions.tuteehub.com/tag/oh-585115" style="font-weight:bold;" target="_blank" title="Click to know more about OH">OH</a>^(-) ] =(10 ^(-4))/( 1) = 10 ^(-4)`<br/>` thereforePOH = 4 rArr pH = 14- 4 = 10 `</body></html>

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