0.01 M solution is given it's pH is .......... (K_a=6.6xx10^(-4))

1.	0.01 M solution is given it's pH is .......... (K_a=6.6xx10^(-4))
Answer» 7.6 8 2.6 `5.0` Solution :`alpha=SQRT(K_a/C)=sqrt((6.6xx10^(-4))/0.01)` `=sqrt(6.6xx10^(-2))`=0.257 `[H^+]=C-alpha` =0.01 x 0.257 `=2.57xx10^(-3)` `[H^+]=sqrt(K_a.C_o)` `=sqrt(6.6xx10^(-4)xx10^(-2))` `[H^+]= 2.57xx10^(-3)` `therefore` pH=-log `(2.57xx10^(-3))` =3-log 2.5 =(3-0.4)=2.60

Discussion