0.01 M solution is given it's pH is .......... (K_a=6.6xx10^(-4))

1.	0.01 M solution is given it's pH is .......... (K_a=6.6xx10^(-4))
Answer» <html><body><p>7.6<br/>8<br/><a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>.6<br/>`5.0`</p>Solution :`alpha=<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(K_a/C)=sqrt((6.6xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>))/0.01)` <br/> `=sqrt(6.6xx10^(-2))`=0.257 <br/> `[<a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>^+]=C-alpha` <br/> =0.01 x 0.257 <br/> `=2.57xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` <br/>`[H^+]=sqrt(K_a.C_o)` <br/> `=sqrt(6.6xx10^(-4)xx10^(-2))` <br/> `[H^+]= 2.57xx10^(-3)` <br/>`therefore` pH=-log `(2.57xx10^(-3))` <br/> =3-log 2.5 <br/> =(3-0.4)=2.60</body></html>

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