0.01 mole solution of .10 volume. H_2O_2 is required to convert 0.01 mol PbS into PbSO_4 ?

0.01 mole solution of .10 volume. H_2O_2 is required to convert 0.01 m

1.	0.01 mole solution of .10 volume. H_2O_2 is required to convert 0.01 mol PbS into PbSO_4 ?
Answer» 11.2 22.4 33.6 44.8 Solution :`PBS+4H_2O_2 to PbSO_4 + 4H_2O` `4H_2O_2 to 4H_2O + 2O_2` To convert 1 mole PbS 1 `PbSO_4` required = 4 mole `H_2O_2` `therefore` to convert 0.01 MOL PbS to `PbSO_4`= (?) `=(0.01xx4)/1`= 0.04 mol `H_2O_2` required STRENGTH of volume=10 `M=V/11.2 =10/11.2 `=0.8928 mol/lit `H_2O_2` 0.8928 mol `H_2O_2 to` 1 LITRE `H_2O_2` `therefore` 0.04 mol `H_2O_2 to` (?) `=(0.04xx1)/0.8928` =0.04480 litre =44.80ml `H_2O_2`