1.

0.023 g of sodium metal is reacted with 100 cm^(3) of water. The pH of the resulting solution is

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a><br/>11<br/>9<br/>12</p>Solution :`Na+H_(2)OrarrNaOH=(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(2)H_(2)` <br/> 1 mole of Na produces 1 mole of <a href="https://interviewquestions.tuteehub.com/tag/naoh-572531" style="font-weight:bold;" target="_blank" title="Click to know more about NAOH">NAOH</a> <br/> `0.023 gNa = (0.023)/(23) "mole" = 10^(-3) "mole"` <br/> `:. ` NaOH <a href="https://interviewquestions.tuteehub.com/tag/produced-592947" style="font-weight:bold;" target="_blank" title="Click to know more about PRODUCED">PRODUCED</a> `= 10^(-3)` mole <br/> `:. [NaOH]=(10^(-3))/(100)xx1000=10^(-2) M` <br/> `:. pOH=2 ` or pH `= 14-2=12`.</body></html>


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