0.023 g of sodium metal is reacted with 100 cm^(3) of water. The pH of the resulting solution is

0.023 g of sodium metal is reacted with 100 cm^(3) of water. The pH of

1.	0.023 g of sodium metal is reacted with 100 cm^(3) of water. The pH of the resulting solution is
Answer» 10 11 9 12 Solution :`Na+H_(2)OrarrNaOH=(1)/(2)H_(2)` 1 mole of Na produces 1 mole of NAOH `0.023 gNa = (0.023)/(23) "mole" = 10^(-3) "mole"` `:. ` NaOH PRODUCED `= 10^(-3)` mole `:. [NaOH]=(10^(-3))/(100)xx1000=10^(-2) M` `:. pOH=2 ` or pH `= 14-2=12`.