1.

0.023 g of sodium metal is reacted with `100 cm^(3)` of water. The pH of the resulting solution isA. 10B. 11C. 9D. 12

Answer» Correct Answer - D
`Na+H_(2)OrarrNaOH=(1)/(2)H_(2)`
1 mole of Na produces 1 mole of NaOH
`0.023 g Na = (0.023)/(23) "mole" = 10^(-3) "mole"`
`:. ` NaOH produced `= 10^(-3)` mole
`:. [NaOH]=(10^(-3))/(100)xx1000=10^(-2) M`
`:. pOH=2 ` or pH `= 14-2=12`.


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