0.03 mole of Ca^(2+) ions is added to a litre of 0.01 M SO_(4)^(2-) solution. Will it cause precipitation of CaSO_(4) ?K_(sp) "for" CaSO_(4)=2.4xx10^(-5).

0.03 mole of Ca^(2+) ions is added to a litre of 0.01 M SO_(4)^(2-) so

1.	0.03 mole of Ca^(2+) ions is added to a litre of 0.01 M SO_(4)^(2-) solution. Will it cause precipitation of CaSO_(4) ?K_(sp) "for" CaSO_(4)=2.4xx10^(-5).
Answer» <html><body><p><br/></p>Solution :In the final solution, `[Ca^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>+)]=0.03 M and [SO_(4)^(2-)]=0.01 M`. Hence, ionic <a href="https://interviewquestions.tuteehub.com/tag/product-25523" style="font-weight:bold;" target="_blank" title="Click to know more about PRODUCT">PRODUCT</a> of `CaSO_(4) = (0.03) (0.01)=3xx10^(-4)` which is greater than `K_(<a href="https://interviewquestions.tuteehub.com/tag/sp-1219706" style="font-weight:bold;" target="_blank" title="Click to know more about SP">SP</a>)`. Hence, precipitation will <a href="https://interviewquestions.tuteehub.com/tag/occur-583012" style="font-weight:bold;" target="_blank" title="Click to know more about OCCUR">OCCUR</a>.</body></html>