0.03 mole of `Ca^(2+)` ions is added to a litre of 0.01 M `SO_(4)^(2-)` solution. Will it cause precipitation of `CaSO_(4)` ? `K_(sp) "for" CaSO_(4)=2.4xx10^(-5)`.

0.03 mole of `Ca^(2+)` ions is added to a litre of 0.01 M `SO_(4)^(2-)

1.	0.03 mole of `Ca^(2+)` ions is added to a litre of 0.01 M `SO_(4)^(2-)` solution. Will it cause precipitation of `CaSO_(4)` ? `K_(sp) "for" CaSO_(4)=2.4xx10^(-5)`.
Answer» Correct Answer - Precipitation of `CaSO_(4)` will occur In the final solution, `[Ca^(2+)]=0.03 M and [SO_(4)^(2-)]=0.01 M`. Hence, ionic product of `CaSO_(4) = (0.03) (0.01)=3xx10^(-4)` which is greater than `K_(sp)`. Hence, precipitation will occur.

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0.03 mole of `Ca^(2+)` ions is added to a litre of 0.01 M `SO_(4)^(2-)` solution. Will it cause precipitation of `CaSO_(4)` ? `K_(sp) "for" CaSO_(4)=2.4xx10^(-5)`.

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