1.

0.049 g of H_(2)SO_(4) is dissolved per litre of thegiven solution . Calculate the pH of the solution.

Answer»


SOLUTION :`[H_(2)SO_(4)]=(0.049)/(98) "mol" L^(-1)=5xx10^(-4)M`.
As `H_(2)SO_(4)rarr2H^(+)+SO_(4)^(2-), [H^(+)]=2XX(5xx10^(-4))=10^(-3)M :. pH = 3`


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