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0.05 g of a gas at 750 mm pressure and 25°C occupy a volume of 46.5 mL. Calculate the molecular mass of the gas. |
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Answer» Solution :In the present case, `P = 750 MM= 750/760 atm, V = 46.5 mL = (46.5)/1000 L`, `T = 25^(@) C = 298 K, w=0.05 g` and `R = 0.0821 L atm K^(-1) "mol"^(-1)` Using the ideal gas equation, `PV = w/M RT` and substituting the values, we have `750/760 xx (46.5)/1000 = 0.05/Mxx 0.0821 xx 298 = 26.66` |
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