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0.05 g of a gas at 750 mm pressure and 25°C occupy a volume of 46.5 mL. Calculate the molecular mass of the gas.

Answer» <html><body><p></p>Solution :In the present case, <br/> `P = 750 <a href="https://interviewquestions.tuteehub.com/tag/mm-1098795" style="font-weight:bold;" target="_blank" title="Click to know more about MM">MM</a>= 750/760 atm, V = 46.5 mL = (46.5)/<a href="https://interviewquestions.tuteehub.com/tag/1000-265236" style="font-weight:bold;" target="_blank" title="Click to know more about 1000">1000</a> <a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>`, <br/> `T = 25^(@) C = 298 K, w=0.05 g` and `<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> = 0.0821 L atm K^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) "mol"^(-1)` <br/> Using the ideal gas equation, `PV = w/M RT` <br/> and substituting the values, we have <br/> `750/760 xx (46.5)/1000 = 0.05/Mxx 0.0821 xx 298 = 26.66`</body></html>


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