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0.05 mole of NaOH is added to 5 liters of water What will be the pH of the solution ?A. 12B. 7C. 2D. 10 |
Answer» Correct Answer - A Conc. of `NaOH=(0.05)/(5)=0.01or10^(-2)M` `[OH^(-)]=10^(-2)M` `[H^(+)]=(K_(w))/([OH^(-)])=(10^(-14))/(10^(-2))=10^(-12)` `pH=-log[H^(+)]=-log10^(-12)=12` |
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