0.06mole of KNO_(3) is added to 100cm^(3) of water at 298K . The enthalpy of KNO_(3) aq. Solution is 35.8kJ mol^(-1). After the solute is dissolved , the temperature of the solution will be

0.06mole of KNO_(3) is added to 100cm^(3) of water at 298K . The entha

1.	0.06mole of KNO_(3) is added to 100cm^(3) of water at 298K . The enthalpy of KNO_(3) aq. Solution is 35.8kJ mol^(-1). After the solute is dissolved , the temperature of the solution will be
Answer» <html><body><p>293K<br/>298K<br/>301K<br/>304 K</p>Solution :Dissoluation of `KNO_(3)` in <a href="https://interviewquestions.tuteehub.com/tag/water-1449333" style="font-weight:bold;" target="_blank" title="Click to know more about WATER">WATER</a> is endothermic, `DeltaH _(sol) = 35.8 kJ mol^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)` <br/> `:.` Heat absorbed when 0.06 mole of `KNO_(3)` is <a href="https://interviewquestions.tuteehub.com/tag/dissolved-956358" style="font-weight:bold;" target="_blank" title="Click to know more about DISSOLVED">DISSOLVED</a> `= 35.8 xx 0.06 kJ = 2148 J` <br/> `q= m xx <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> xx DeltaT` <br/> `:. 2148 = 100 xx 4.184 xx DeltaT` or `DeltaT = 5K` <br/> `:. `<a href="https://interviewquestions.tuteehub.com/tag/temperatureof-2293939" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATUREOF">TEMPERATUREOF</a> the solution `= 298 -5= 293K`.</body></html>