1.

0.06mole of KNO_(3) is added to 100cm^(3) of water at 298K . The enthalpy of KNO_(3) aq. Solution is 35.8kJ mol^(-1). After the solute is dissolved , the temperature of the solution will be

Answer»

293K
298K
301K
304 K

Solution :Dissoluation of `KNO_(3)` in WATER is endothermic, `DeltaH _(sol) = 35.8 kJ mol^(-1)`
`:.` Heat absorbed when 0.06 mole of `KNO_(3)` is DISSOLVED `= 35.8 xx 0.06 kJ = 2148 J`
`q= m xx C xx DeltaT`
`:. 2148 = 100 xx 4.184 xx DeltaT` or `DeltaT = 5K`
`:. `TEMPERATUREOF the solution `= 298 -5= 293K`.


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