0.075 g of a monobasic acid required 10 mL of N//12 NaOH solution for complete neutralisation. Calculate the molecular mass of the acid

0.075 g of a monobasic acid required 10 mL of N//12 NaOH solution for

1.	0.075 g of a monobasic acid required 10 mL of N//12 NaOH solution for complete neutralisation. Calculate the molecular mass of the acid
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of the organic acid taken = 0.075 g <br/> Volume of `N//12 NaOH` required for neutralisation = 10 mL <br/> <a href="https://interviewquestions.tuteehub.com/tag/step-25533" style="font-weight:bold;" target="_blank" title="Click to know more about STEP">STEP</a> I. Calculation of equivalent mass of the acid. <br/> `10 mL` of `N//12 NaOH -= 0.075 g` of acid <br/> `:.` 1000 mL of `1N NaOH = ((0.075 g) xx (1000 mL) xx (1N))/((10 mL) xx (N//12)) = 90 g` <br/> 1000 mL of 1 N NaOH solution contain one gram equivalent of base and it reacts with one gram equivalent of the acid. <br/> `:.` Equivalent mass of the acid = 90 <br/> step <a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>. Calculation of the molecular mass of the acid. <br/> Molecular mass = Equivalent mass `xx` Basicity <br/> `= 90 xx 1 = 90` [Foe a monobasic acid, basicity = 1]</body></html>