0.075 g of a monobasic acid required 10 mL of N//12 NaOH solution for complete neutralisation. Calculate the molecular mass of the acid

0.075 g of a monobasic acid required 10 mL of N//12 NaOH solution for

1.	0.075 g of a monobasic acid required 10 mL of N//12 NaOH solution for complete neutralisation. Calculate the molecular mass of the acid
Answer» SOLUTION :MASS of the organic acid taken = 0.075 g Volume of `N//12 NaOH` required for neutralisation = 10 mL STEP I. Calculation of equivalent mass of the acid. `10 mL` of `N//12 NaOH -= 0.075 g` of acid `:.` 1000 mL of `1N NaOH = ((0.075 g) xx (1000 mL) xx (1N))/((10 mL) xx (N//12)) = 90 g` 1000 mL of 1 N NaOH solution contain one gram equivalent of base and it reacts with one gram equivalent of the acid. `:.` Equivalent mass of the acid = 90 step II. Calculation of the molecular mass of the acid. Molecular mass = Equivalent mass `xx` Basicity `= 90 xx 1 = 90` [Foe a monobasic acid, basicity = 1]