0.0755 g of selenium vapours occupying a volume of 114.2 mL at 700^(@)C and 185 mm of Hg. The vapours are in equilibrium as: Se_(6(g))hArr3Se_(2(g)) Calculate: (i) Degree of dissociation of Se, (ii) K_(p), (iii) K_(c). Atomic weight of Se is 79.

0.0755 g of selenium vapours occupying a volume of 114.2 mL at 700^(@)

1.	0.0755 g of selenium vapours occupying a volume of 114.2 mL at 700^(@)C and 185 mm of Hg. The vapours are in equilibrium as: Se_(6(g))hArr3Se_(2(g)) Calculate: (i) Degree of dissociation of Se, (ii) K_(p), (iii) K_(c). Atomic weight of Se is 79.
Answer» <html><body><p></p>Solution :(`i`) `<a href="https://interviewquestions.tuteehub.com/tag/59-326069" style="font-weight:bold;" target="_blank" title="Click to know more about 59">59</a>%`, (`<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>`) `0.168 <a href="https://interviewquestions.tuteehub.com/tag/atm-364409" style="font-weight:bold;" target="_blank" title="Click to know more about ATM">ATM</a>`, (`<a href="https://interviewquestions.tuteehub.com/tag/iii-497983" style="font-weight:bold;" target="_blank" title="Click to know more about III">III</a>`) `<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>.633xx10^(-5) mol^(2) litre^(-2)` ,</body></html>