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0.078 g of a hydrocarbon occupy 22.414 mL of volume at S.T.P. The empirical formula of the hydrocarbon is CH. The molecular formula of hydrocarbon isA. `C_(2)H_(2)`B. `C_(6)H_(6)`C. `C_(8)H_(8)`D. `C_(4)H_(4)` |
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Answer» Correct Answer - B 22.414 mL of gaseous hydrocarbon at S.T.P. has mass = 0.078 g 22414 mL of gaseous hydrocarbon at S.T.P. will have mass = 78 g `:.` Molar mass of hydrocarbon `= 78 gmol^(-1)` Empirical formula mass of hydrocarbon (CH) `= 12+1=13` `:. n = ("Molecular mass")/("E.F. mass") = (78)/(13) =6` `:.` Molecular mass of hydrocarbon `= (CH)_(6)=C_(6)H_(6)` |
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