1.

0.078 g of a hydrocarbon occupy 22.414 mL of volume at S.T.P. The empirical formula of the hydrocarbon is CH. The molecular formula of hydrocarbon isA. `C_(2)H_(2)`B. `C_(6)H_(6)`C. `C_(8)H_(8)`D. `C_(4)H_(4)`

Answer» Correct Answer - B
22.414 mL of gaseous hydrocarbon at S.T.P. has mass = 0.078 g
22414 mL of gaseous hydrocarbon at S.T.P. will have mass = 78 g
`:.` Molar mass of hydrocarbon `= 78 gmol^(-1)`
Empirical formula mass of hydrocarbon (CH)
`= 12+1=13`
`:. n = ("Molecular mass")/("E.F. mass") = (78)/(13) =6`
`:.` Molecular mass of hydrocarbon
`= (CH)_(6)=C_(6)H_(6)`


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