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`0.0833 `mol of carbohydrate of empirical formula `CH_(2)O` contain `1 g ` of hydrogen. The molecular formula of the carbohydrate isA. `C_(6)H_(12)O_(6)`B. `C_(5)H_(10)O_(5)`C. `C_(3)H_(4)O_(3)`D. `C_(6)H_(12)O_(5)` |
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Answer» Correct Answer - A `0.833 mol` of carbihydrate contains `10 g` hydrogen. Thus, `1 mol` of the compound will certain `(10 g)/(0.833 mol) = 12 g mol^(-1)` This implies that `1` molecule of carbohydrate contains `12 u` of `H (or (12 u)/(1 u "atom"^(-1)) = 12 at oms of H)` `:.` Molecular formula `= C_(6)H_(12)O_(6)` |
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