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0.1 g of an organic compound gave 0.222g of Mg_(2)P_(2)O_(7). What is the percentage of phosphorus in the compound ?

Answer» <html><body><p>&lt;<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>&gt;0.32<br/>0.42<br/>0.52<br/>0.62</p>Solution :Amountof `P=(0.<a href="https://interviewquestions.tuteehub.com/tag/222-294559" style="font-weight:bold;" target="_blank" title="Click to know more about 222">222</a> <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 62)/(222) = 0.062 <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> ` <br/> `therefore " % of" P= (0.062)/(0.1) xx 100 =62.`</body></html>


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