1.

0.1 g of an organic compound gave 0.222g of Mg_(2)P_(2)O_(7). What is the percentage of phosphorus in the compound ?

Answer»

<P>0.32
0.42
0.52
0.62

Solution :Amountof `P=(0.222 XX 62)/(222) = 0.062 G `
`therefore " % of" P= (0.062)/(0.1) xx 100 =62.`


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