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0.1 g of metal combines with 46.6 mL of oxygen at STP. The equivalent weight of metal is

Answer» <html><body><p>12<br/>24<br/>18<br/>36<br/></p>Solution :a) 1 mole of `O_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` = 4 equivalent of <a href="https://interviewquestions.tuteehub.com/tag/oxygen-1144542" style="font-weight:bold;" target="_blank" title="Click to know more about OXYGEN">OXYGEN</a> <br/> 22400 <a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a> of `O_(2)` = 4 equivalent of oxygen <br/> 46.6 mL of `O_(2)` = (4/22400) xx 46.6 = 0.00832 eq. <br/> Equivalent of metal = Equivalent of oxygen <br/> (<a href="https://interviewquestions.tuteehub.com/tag/weight-1451304" style="font-weight:bold;" target="_blank" title="Click to know more about WEIGHT">WEIGHT</a>)/(Equivalent) = 0.00832 <br/> 0.1/E = 0.00832 `rARr` E= (0.1)/(0.00832) = 12.0</body></html>


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