0.1 g of metal combines with 46.6 mL of oxygen at STP. The equivalent weight of metal is

0.1 g of metal combines with 46.6 mL of oxygen at STP. The equivalent

1.	0.1 g of metal combines with 46.6 mL of oxygen at STP. The equivalent weight of metal is
Answer» 12 24 18 36 Solution :a) 1 mole of `O_(2)` = 4 equivalent of OXYGEN 22400 ML of `O_(2)` = 4 equivalent of oxygen 46.6 mL of `O_(2)` = (4/22400) xx 46.6 = 0.00832 eq. Equivalent of metal = Equivalent of oxygen (WEIGHT)/(Equivalent) = 0.00832 0.1/E = 0.00832 `rARr` E= (0.1)/(0.00832) = 12.0