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0.1 g of metal combines with 46.6 mL of oxygen at STP. The equivalent weight of metal isA. 12B. 24C. 18D. 36 |
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Answer» a) 1 mole of `O_(2)` = 4 equivalent of oxygen 22400 mL of `O_(2)` = 4 equivalent of oxygen 46.6 mL of `O_(2)` = (4/22400) xx 46.6 = 0.00832 eq. Equivalent of metal = Equivalent of oxygen (Weight)/(Equivalent) = 0.00832 0.1/E = 0.00832 `rARr` E= (0.1)/(0.00832) = 12.0 |
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