1.

0.1 M copper sulphate solution in which copper electrode is dipped at 25^@C. Calculate the electrode potential of copper. [Given E_(Cu^(2+)|Cu)^@ = 0.34]

Answer»

Solution :Given that
`[CU^(2+)] = 0.1 M`
`E_(Cu^(2+)|Cu)^@ = 0.34`
`E_("cell") = ?`
Cell reaction is `Cu^(2+) (aq) + 2r^(-) to Cu(s)`
`E_("cell") = E^(@) - (0.0591)/n log ([Cu])/([Cu^(2+)]) = 0.34 - (0.0591)/2 log 1/(0.1)`
`- 0.34 - 0.0296 = 0.31 V`.


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