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0.1 M HQ acid has pH=3 then findits ionization constant.

Answer» <html><body><p>`3xx10^(-1)`<br/>`1xx10^(-3)`<br/>`1xx10^(-5)`<br/>`1xx10^(-7)`</p>Solution :`{:(,HQoversettolarr, H^+ +, Q^-),("Initial " , 0.1 M, O,O),("Ionized <a href="https://interviewquestions.tuteehub.com/tag/mole-1100299" style="font-weight:bold;" target="_blank" title="Click to know more about MOLE">MOLE</a>",<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>,x,x),(,darr,darr,darr),("Mole at <a href="https://interviewquestions.tuteehub.com/tag/equilibrium-974342" style="font-weight:bold;" target="_blank" title="Click to know more about EQUILIBRIUM">EQUILIBRIUM</a>",0.1-x,x,x):}` <br/> pH=3 <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> [H^+]=10^(-3)` <br/> `therefore x=10^(-3)` <br/> `therefore K_a=((x)xx(x))/(0.1-x)` <br/> `=(10^(-3))^2/(0.1-10^(-3)) approx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>)/0.1 = 1xx10^(-5)`</body></html>


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