0.1 M KI and 0.2 M `AgNO_(3)` are mixed in 3 : 1 volume ratio. The depression of freezing point of the resulting solution will be [`K_(b)(H_(2)O) = 1.86 K kg "mol"^(-1)`]:A. 3.72 KB. 1.86 KC. 0.93 KD. 0.279 K

0.1 M KI and 0.2 M `AgNO_(3)` are mixed in 3 : 1 volume ratio. The dep

1.	0.1 M KI and 0.2 M `AgNO_(3)` are mixed in 3 : 1 volume ratio. The depression of freezing point of the resulting solution will be [`K_(b)(H_(2)O) = 1.86 K kg "mol"^(-1)`]:A. 3.72 KB. 1.86 KC. 0.93 KD. 0.279 K
Answer» Correct Answer - d

Discussion

No Comment Found

Related InterviewSolutions

Which of the folloeing statement is (are) incorrect?A. 0.1 M KCl solution will have the same osmotic pressure as 0.1 M glucose solutionB. 0.1 M KCl solution will have the same boiling point as 0.1 M urea solutionC. 0.1 m glucose and 0.1 m urea are ismoticD. 0.1 m `MgCl_(2)` solution will have less relative lowering of vapour pressure than 0.1 m NaCl
A complex is represented as `CoCl_(3) . XNH_(3)`. Its `0.1` molal solution in aqueous solution shows `Delta T_(f) = 0.558^(circ). (K_(f)` for `H_(2)O` is `1.86 K "molality"^(-1))` Assuming `100%` ionisation of complex and co-ordination number of `Co` as six, calculate formula of complex.A. `[Co(NH_(3)_(4)CL_(2)]Cl`B. `[Co(NH_(3))_(5)Cl]Cl_(2)`C. `[Co(NH_(3))_(4)CL_(2)]Cl`D. none of these
Calculate the molecular weight of a substance whose `7.0%` (by weight) solution in water freezes at `-0.89^(@)C`. `(k_(f) "for" H_(2)O=1.86K"molality"^(-1)`).
A living cell contains a solution which is isotonic with 0.2 M glucose solution. What osmotic pressure develops when the cell is placed in 0.05 M `BaCl_(2)`solution at 300 K ?A. 1.23 atmB. 3.69 atmC. 6.15 atmD. None of these
When `250 mg` of eugenol is added to `100 g` of camphor `(K_(f) = 39.7K "molality"^(-1))`, it lowered the freezing point by `0.62^(@)C`. The molar mass of eugenol is:A. (a) `160g mol^(-1)`B. (b) `165g mol^(-1)`C. (c ) `200g mol^(-1)`D. (d) `250g mol^(-1)`
Two liquid A and B have vapour pressure in the ratio ` P_A^(@) : P_B^(@)`=1.3 at a certain temperature.Assume A and B from an ideal solution and the ratio of mole fractions of A to B in the vapour phase is 4 : 3, then the mole fraction of B in the solution at the same tempreature is :A. `1/5`B. `2/3`C. `4/5`D. `1/4`
For a ideal liquid solution with `P_A^(@)gtP_A^(@)`, which relation between` X_(A)` ((mole fraction of A in liquid phase) and `Y_(A)`(mole fraction of A in vapour phese) is correct ?A. `Y_(a) lt Y_(b)`B. `X_(A) gtX_(B)`C. `(Y_(A))/(Y_(B)) gt( X_(A))/(X_(B))`D. `(Y_(A))/(Y_(B)) lt( X_(A))/(X_(B))`
1.0 g of a monobassic acid HA in 100 g water lowers the freezing point by 0.155 K. IF 0.75 g, of same acid requires 25 mL of N/5 NaOH solution for complete neutralisation then %, degree of ionization of acid is (`K_(f) of H_(2)O = 1.86 K kg "mol"^(-1)`):A. 0.2B. 0.25C. 0.4D. 0.5
An ideal solution has two components A is more volatile than B, i.e.`P_A^(@)gtP_B^(@)` and also` p_A^(@) gt P_("total")`. If `X_(A) andY_(A)` are mole fraction of components A in liquid and vapour phases, than :A. `X_(A) = Y_(A)`B. `X_(A) gt Y_(A)`C. `X_(A) lt Y_(A)`D. Data insuffcient
100 g of `C_(6)H_(12)O_(6)` (aq.) solution has vapour pressure is equal to 40 torr at certain temperature. Vapour pressure of `H_(2)O`(l) is 40.18 torr at same temperature. If this solution is cooled to `-0.93^(@)C`, what mass of ice will be separated out? (`K_(f) = 1.86 kg "mol"^(-1)`):A. 95.5 gB. 4.5 gC. 45.5 gD. 47.8 g

0.1 M KI and 0.2 M `AgNO_(3)` are mixed in 3 : 1 volume ratio. The depression of freezing point of the resulting solution will be [`K_(b)(H_(2)O) = 1.86 K kg "mol"^(-1)`]:A. 3.72 KB. 1.86 KC. 0.93 KD. 0.279 K

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment