0.1 M-KMnO_(4) is used for the following titration. How much volume of the solution in ml will be required to react with 0.158 gm of Na_(2)S_(2)O_(3)? S_(2)O_(3)^(2-)+MnO_(4)^(-)+H_(2)OtoMnO_(2)(s)+SO_(4)^(2-)+OH^(-)

0.1 M-KMnO_(4) is used for the following titration. How much volume of

1.	0.1 M-KMnO_(4) is used for the following titration. How much volume of the solution in ml will be required to react with 0.158 gm of Na_(2)S_(2)O_(3)? S_(2)O_(3)^(2-)+MnO_(4)^(-)+H_(2)OtoMnO_(2)(s)+SO_(4)^(2-)+OH^(-)
Answer» <html><body><p>80 <a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a><br/>26.67 ml<br/>13.33 ml<br/>16 ml</p>Solution :eq. `KMnO_(4)` = eq. `Na_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)S_(2)O_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` <br/> `(0.1xxV_(mL))/(1000)xx3=(0.158)/(158)xx8impliesV_(mL)=26.67mL`</body></html>