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`0.1 M NaOH (aq)` solution having density `1.2 gm//ml` will have molalityA. `0.2 M`B. `0.15 M`C. `0.08 M`D. `0.12 M` |
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Answer» Correct Answer - C `(d)/(M) = (1)/(m) + (MM)/(1000)` `(1.2)/(0.1) = (1)/(m) + (40)/(1000)` `m = 0.08 m` |
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