1.

`0.1 M NaOH (aq)` solution having density `1.2 gm//ml` will have molalityA. `0.2 M`B. `0.15 M`C. `0.08 M`D. `0.12 M`

Answer» Correct Answer - C
`(d)/(M) = (1)/(m) + (MM)/(1000)`
`(1.2)/(0.1) = (1)/(m) + (40)/(1000)`
`m = 0.08 m`


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