0.1 MHCl and 0.1 M H_(2)SO_(4), each of volume 2 ml are mixed and the volume is made up to 6 ml by adding 2 ml of 0.01 N NaCl solution. The pH of the resulting mixture is

0.1 MHCl and 0.1 M H_(2)SO_(4), each of volume 2 ml are mixed and the

1.	0.1 MHCl and 0.1 M H_(2)SO_(4), each of volume 2 ml are mixed and the volume is made up to 6 ml by adding 2 ml of 0.01 N NaCl solution. The pH of the resulting mixture is
Answer» `1.17` `1.0` `0.3` log 2 - log 3 Solution :2 MLOF 0.1 M HCl =0.2 MILLIMOLE of HCl = 0.2 millimole of `H^(+)` ion 2 ml of 0.1 M `H_(2)SO_(4)= 0 .2` millimole of `H_(2)SO_(4)` = 0.4 millimole of `H^(+)` ion Total `H^(+)` ions = 0.6 millimole Total volume = 6 ml `:. [H^(+)]=(0.6)/(6)M=0.1 M =10^(-1)M:. pH = 1`.