0.1 MHCl and 0.1 M H_(2)SO_(4), each of volume 2 ml are mixed and the volume is made up to 6 ml by adding 2 ml of 0.01 N NaCl solution. The pH of the resulting mixture is

0.1 MHCl and 0.1 M H_(2)SO_(4), each of volume 2 ml are mixed and the

1.	0.1 MHCl and 0.1 M H_(2)SO_(4), each of volume 2 ml are mixed and the volume is made up to 6 ml by adding 2 ml of 0.01 N NaCl solution. The pH of the resulting mixture is
Answer» <html><body><p>`1.17`<br/>`1.<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>`<br/>`0.3`<br/>log 2 - log 3</p>Solution :2 <a href="https://interviewquestions.tuteehub.com/tag/mlof-2837377" style="font-weight:bold;" target="_blank" title="Click to know more about MLOF">MLOF</a> 0.1 M HCl =0.2 <a href="https://interviewquestions.tuteehub.com/tag/millimole-2833492" style="font-weight:bold;" target="_blank" title="Click to know more about MILLIMOLE">MILLIMOLE</a> of HCl <br/> = 0.2 millimole of `<a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>^(+)` ion<br/>2 ml of 0.1 M `H_(2)SO_(4)= 0 .2` millimole of `H_(2)SO_(4)` <br/> = 0.4 millimole of `H^(+)` ion<br/> Total `H^(+)` ions = 0.6 millimole<br/> Total volume = 6 ml <br/> `:. [H^(+)]=(0.6)/(6)M=0.1 M =<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-1)M:. pH = 1`.</body></html>