0.1 mol of CH3NH2 (Kb=6×10−4) is added to 0.08 mol of HCl and the s – InterviewSolution

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1.	0.1 mol of CH3NH2 (Kb=6×10−4) is added to 0.08 mol of HCl and the solution is diluted to 1 L. The hydrogen ion concentration in the solution is:
Answer» 0.1 mol of $C H_{3} N H_{2} (K_{b} = 6 \times 10^{- 4})$ is added to 0.08 mol of $H C l$ and the solution is diluted to $1 L$ . The hydrogen ion concentration in the solution is:

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