InterviewSolution
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0.1 "mole" `AgNO_(3)` is added in 250 mL of saturated solution of AgCl at `25^(@)C` without changing volume. Given: `K_(sp)` of `AgCl=1.0xx10^(-10)M^(2)` Ionic conductance of `Ag^(+)"ion"=60Omega^(-1)cm^(2) "mol"^(-1)` Ionic conductance of `Cl^(-)` ion =`75Omega^(-1)cm^(2) "mol"^(-1)` Ionic conductance of `NO_(3)^(-) "ion"=75 Omega^(-1)` `[Cl^(-)]`in the final solution is equal to :A. `10^(9)M`B. `2.5xx10^(-10)M`C. `10^(-5)M`D. `2.5xx10^(-7)M` |
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Answer» Correct Answer - B |
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