1.

0.1 mole of KMnO_(4) present in 500 ml solution got converted into K_(2)MnO_(4). The concentration of KMnO_(4) is

Answer»

0.2 M
0.2 N
1 N
0.04 N

Solution :n-factor = `1,M=(0.1)/(0.5)=0.2M=0.2N`


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