0*1 mole of N_(2)O_(4) (g) was sealed in a tube under atmospheric conditions at 25^(@)C. Calculate the number of moles of NO_(2) (g) present if the equilibrium N_(2)O_(4) (g) hArr 2 NO_(2)is reached after some time (K_(p) = 0 *14).

0*1 mole of N_(2)O_(4) (g) was sealed in a tube under atmospheric cond

1.	01 mole of N_(2)O_(4) (g) was sealed in a tube under atmospheric conditions at 25^(@)C. Calculate the number of moles of NO_(2) (g) present if the equilibrium N_(2)O_(4) (g) hArr 2 NO_(2)is reached after some time (K_(p) = 0 14).
Answer» <html><body><p></p>Solution :` {: (,N_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)O_(4)(<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>),hArr,2NO_(2)(g),) ,("Intial amounts",0.1 "mole",,0,), ("At equilibrium " ,(01 -x),,2x," <a href="https://interviewquestions.tuteehub.com/tag/total-711110" style="font-weight:bold;" target="_blank" title="Click to know more about TOTAL">TOTAL</a> " 01 +x "moles"):}`<br/> As P=1atm, ` p_(N_(2)O_(4)) = (01 -x)/(01 +x), p_(NO_(2))= 2/(01 + x) atm `<br/>` K_(p) - (p_(N_(O_(4)))^(2))/p_(N_(2)O_(4)) = (2x // (01 + x))^(2)/((01-x) //( 01 +x))= (4x^(2))/((01- x) ( 01 +x) )= (4x^(2))/(001 - x^(2) )` <br/> ` :. (4x^(2))/(001 - x^(2) = 014 )or 414x^(2) = 00014or x = 0 018 ` <br/> ` :. " No. of moles of " NO_(2) " at equilibrium " = 2x = 2 xx 0* 018= 0* 036 "mole" `</body></html>