1.

0.10 moole of AgCI_((s)) is added to 1 litre of H_(2)O. Next crystal of NaBr are added until 75% of the AgCI is concerted to AgBr_((s)), the less soluble silver halide. What is Br^(-) at this point? K_(SP) ofAgCI is 1.78xx10^(-10) and K_(SP) of AgBr is 5.25xx10^(-13).

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`2.2xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)M;`</body></html>


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