0.12 g of an organic compound containing phosphorus gave 0.22 g of Mg_(2)P_(2)O_(7) by the usual analysis. Calculate the percentage of phosphorus in the compound.

0.12 g of an organic compound containing phosphorus gave 0.22 g of Mg_

1.	0.12 g of an organic compound containing phosphorus gave 0.22 g of Mg_(2)P_(2)O_(7) by the usual analysis. Calculate the percentage of phosphorus in the compound.
Answer» <html><body><p></p>Solution :Here, the mas of the compound taken = 0.13 <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> <br/> Mass of `Mg_(2)P_(2)O_(7) -= 2g` atoms of P or `(2 xx 24 + 2 xx 31 + 16 xx 7) = 222g` of `Mg_(2)P_(2)O_(7) -= 62 g` of P<br/> i.e., 222g of `Mg_(2)P_(2)O_(7)` <a href="https://interviewquestions.tuteehub.com/tag/contain-409810" style="font-weight:bold;" target="_blank" title="Click to know more about CONTAIN">CONTAIN</a> <a href="https://interviewquestions.tuteehub.com/tag/phosphorus-1153299" style="font-weight:bold;" target="_blank" title="Click to know more about PHOSPHORUS">PHOSPHORUS</a> = 62 g <br/> `:.` 0.22 g of `Mg_(2)P_(2)O_(7)` will contain phosphorus `= (62)/(222) xx 0.22 g` <br/> But this is the amount of phosphorus present in 0.12 g of the organic compound. <br/> `:.` Percentage of phosphorus `= (62)/(222) xx (0.22)/(0.12) xx 100 = 51.20`</body></html>