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0.126 g of acid required 20 mL of 0.1 N NaOH for complete neutralisation. The equivalent mass of an acid isA. `45`B. `53`C. `40`D. `63` |
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Answer» Correct Answer - D Let equivalent mass be E `:.` g-equivalent of acid `= (0.126)/(E)` G-equivalents of acid = G equi. Of base or `(0.126)/(E) = 20xx10^(-3)xx0.1` or `E = (0.126xx10^(3))/(20xx0.1)=63` |
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