0.12g organic compound gave 0.22g Mg_(2)P_(2)O_(7). What is the percentage of phosphorus in compound? (P= 31) (Molar mass of Mg_(2)P_(2)O_(7)= 222g)

0.12g organic compound gave 0.22g Mg_(2)P_(2)O_(7). What is the percen

1.	0.12g organic compound gave 0.22g Mg_(2)P_(2)O_(7). What is the percentage of phosphorus in compound? (P= 31) (Molar mass of Mg_(2)P_(2)O_(7)= 222g)
Answer» Solution :`2P rarr Mg_(2)P_(2)O_(7)` % `P =("MASS of 2P")/("MOLAR mass of" Mg_(2)P_(2)O_(7)) xx ("mass of "Mg_(2)P_(2)O_(7))/("molar mass of compound") xx 100` `=(62)/(222) xx (0.22)/(0.12) xx 100= 51.20%`