0.12g organic compound gave 0.22g Mg_(2)P_(2)O_(7). What is the percentage of phosphorus in compound? (P= 31) (Molar mass of Mg_(2)P_(2)O_(7)= 222g)

0.12g organic compound gave 0.22g Mg_(2)P_(2)O_(7). What is the percen

1.	0.12g organic compound gave 0.22g Mg_(2)P_(2)O_(7). What is the percentage of phosphorus in compound? (P= 31) (Molar mass of Mg_(2)P_(2)O_(7)= 222g)
Answer» <html><body><p></p>Solution :`2P rarr Mg_(2)P_(2)O_(<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>)` <br/> % `P =("<a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of 2P")/("<a href="https://interviewquestions.tuteehub.com/tag/molar-562965" style="font-weight:bold;" target="_blank" title="Click to know more about MOLAR">MOLAR</a> mass of" Mg_(2)P_(2)O_(7)) xx ("mass of "Mg_(2)P_(2)O_(7))/("molar mass of compound") xx 100` <br/> `=(<a href="https://interviewquestions.tuteehub.com/tag/62-330265" style="font-weight:bold;" target="_blank" title="Click to know more about 62">62</a>)/(222) xx (0.22)/(0.12) xx 100= 51.20%`</body></html>