0.13 g of Cu, when treated with AgNO_3 solution, displaced 0.433 g of Ag. 0.13 g of AI, when treated with CuSO_4 solution displaced 0.47g of Cu. 1.17 g of AI displaces 0.13 g of hydrogen from an acid. Find the equivalent weight of Ag if equivalent weights of Cu and Al are not known.

0.13 g of Cu, when treated with AgNO_3 solution, displaced 0.433 g of

1.	0.13 g of Cu, when treated with AgNO_3 solution, displaced 0.433 g of Ag. 0.13 g of AI, when treated with CuSO_4 solution displaced 0.47g of Cu. 1.17 g of AI displaces 0.13 g of hydrogen from an acid. Find the equivalent weight of Ag if equivalent weights of Cu and Al are not known.
Answer» <html><body><p></p>Solution :`underset(0.13g)(Cu)+ AgNO_3 to underset(0.433g)(Ag) ""...(1)` <br/> `underset(0.13g)(AI)+ CuSO_4 to underset(0.47g)(Cu)""...(2)` <br/> `underset(1.17g)(AI) + "Acid" to underset(0.13g)(H_2)""...(3)` <br/> For Eqn. (3) : <a href="https://interviewquestions.tuteehub.com/tag/eq-446394" style="font-weight:bold;" target="_blank" title="Click to know more about EQ">EQ</a>. of <a href="https://interviewquestions.tuteehub.com/tag/al-370666" style="font-weight:bold;" target="_blank" title="Click to know more about AL">AL</a> = eq. of hydrogen <br/> `therefore (1.17)/("eq. <a href="https://interviewquestions.tuteehub.com/tag/w-729065" style="font-weight:bold;" target="_blank" title="Click to know more about W">W</a>. of AI")= (0.13)/(1),` eq. <a href="https://interviewquestions.tuteehub.com/tag/wt-1462289" style="font-weight:bold;" target="_blank" title="Click to know more about WT">WT</a>. of Al is 9. <br/> For Eqn. (2) : eq. of Al = eq. of Cu <br/> `therefore (0.13)/(9) = (0.47)/("eq. wt. of Cu"),` eq. wt. of Cu= 32.5. <br/> For Eqn. (1) : eq. of Cu = eq. of Ag <br/> `therefore (0.13)/( 32.5) = (0.433)/("eq. wt. of Ag")` <br/> eq. wt. of Ag= 108.25.</body></html>