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0.15 g of iodoform gave 0.2682 g of AgI. Calculate the percentage of iodine. |
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Answer» Solution :Weight of compound = 0.15 G Weight of silver IODIDE = 0.2682 g Molecular weight of silver iodide `= 108 + 127 = 235` 235 g of silver iodide contains 127 g of iodine 0.2682 g of AgI contains `=(127xx0.2682)/(235)` `=0.144 g` iodine 0.15 g of compound contains 0.144 g of iodine 100 g of compound contains `=(100xx0.1449)/(0.15)=96.6g` `therefore"Percentage of iodine"=96.6` |
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