0.15 g of iodoform gave 0.2682 g of AgI. Calculate the percentage of i

1.	0.15 g of iodoform gave 0.2682 g of AgI. Calculate the percentage of iodine.
Answer» <html><body><p></p>Solution :Weight of compound = 0.15 <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> <br/> Weight of silver <a href="https://interviewquestions.tuteehub.com/tag/iodide-1051130" style="font-weight:bold;" target="_blank" title="Click to know more about IODIDE">IODIDE</a> = 0.2682 g <br/> Molecular weight of silver iodide `= 108 + 127 = <a href="https://interviewquestions.tuteehub.com/tag/235-1826120" style="font-weight:bold;" target="_blank" title="Click to know more about 235">235</a>` <br/> 235 g of silver iodide contains 127 g of iodine <br/> 0.2682 g of AgI contains `=(127xx0.2682)/(235)` <br/> `=0.144 g` iodine <br/> 0.15 g of compound contains 0.144 g of iodine <br/> <a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a> g of compound contains `=(100xx0.1449)/(0.15)=96.6g` <br/> `therefore"Percentage of iodine"=96.6`</body></html>

0.15 g of iodoform gave 0.2682 g of AgI. Calculate the percentage of iodine.