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0.15 gm of an organic compound gave 0.12 gm of silver bromide by the carius method. Find the percentage of bromine in the compound. |
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Answer» Molar mass of AgBr = 108 + 80 = 188 g `mol^(-1)` 188 g AgBr contains 80 g bromine 0.12 g AgBr contains `(80xx0.12)/188` g bromine Percentage of bromine=`(80xx0.12xx100)/(188xx0.15)` =34.04% |
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