InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
0*15mole of CO taken in 2*5 l flask is maintained at 750 K along with catalyst so that the following reaction can take place : CO (g) + 2 H_(2) (g) hArr CH_(3)OH (g) Hydrogen is introduced until the total pressure of the system is 8*5 atmosphere at equilibrium and 0*08 mole of methanol is formed . Calculate (i) K_(p) and K_(c) and (ii) the final pressure if the same amount of CO and H_(2) as before are used but with no catalyst so that the reaction does not take place. |
| Answer» <html><body><p></p>Solution :`{:((i),CO,+,2H_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>),hArr,CH_(3)<a href="https://interviewquestions.tuteehub.com/tag/oh-585115" style="font-weight:bold;" target="_blank" title="Click to know more about OH">OH</a>) ,("Intialy :",0*15 "mole",,,,) ,("At eqm:",0*15 - 0*08 "mole",,,,), (,=0*017 "mole",,,,):}` <br/> Total volume, `V= 2*5 L`<br/> Total <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a>` P+ 8*5 "atm", T= 750 "K" `<br/>`" <a href="https://interviewquestions.tuteehub.com/tag/applying-1982651" style="font-weight:bold;" target="_blank" title="Click to know more about APPLYING">APPLYING</a> "PV= nRT,`<br/>we get` 8*5 xx2*5 = n xx0* 0821 * 750or n = 0* 345 "mole" `<br/> ` :."No. of moles of " H_(2) " at equilibrium "= 0* 345 - ( 0* 017 + 0*08 ) = 0* 248 " mol "`<br/>` P_(CO)= (0* 017 )/(0*345 ) xx 8*5 "atm"= 0* 42 "atm" ` <br/>` p_(H_(2)) = ( 0*248 )/(0* 345) xx8*5 "atm " = 6* 11 "atm "`<br/> ` P _(CH_(3)OH) = (0*8)/(0*345) xx 8*5 "atm"= 1* 97 "atm" `<br/> ` K_(p) = (P_(CH_(3)OH))/(P_(CO) xx P_(H_(2)))= (1*97 )/(0*42 xx (6* 11)^(2) )= 0* 1256 `<br/> ` K_(c)= ([CH_(3) OH])/([CO][H_(2)]^(2))=(0* 08 //2*5)/((0* 017 //2*5 )(0*248 //2*5)^(2)) = 478 *2` n(ii) No. of moles of `H_(2) " taken intially " = 0* 248 + 2 xx 0* 08 = 0* 308 `<br/> No. of moles of CO taken intially `= 0*15`<br/> ApplyingPV = nRt , ` P xx 2*5 = 0* 458 xx 0* 0821 xx 750or P = 11* 28 "atm " `.</body></html> | |